Question

Write a function definition for a function called even that takes one argument of type \(i n t\) and returns a bool value. The function returns true if its one argument is an even number; otherwise, it returns false.

Short answer

Question: Write a function called "even" that takes an integer as an argument and returns a boolean value. The function should return true if the integer is even and false otherwise.

Step-by-step solution

Write the function signature

To begin, write the function signature which includes the function's name `even`, the input argument `int` for the integer, and `bool` as the return type for the function. ```cpp bool even(int num); ```

Implement the function body

Inside the function, use an if statement to check if the integer `num` is even. If it is (i.e., `num % 2 == 0`), return `true`. Otherwise, return `false`. Here's the complete function implementation: ```cpp bool even(int num) { if (num % 2 == 0) { return true; } else { return false; } } ```

Alternate Implementations

As an alternative, you can also use a ternary operator instead of the if-else statement to make the function shorter and more concise: ```cpp bool even(int num) { return (num % 2 == 0) ? true : false; } ``` Or even more simply, just return the result of the expression since it is a boolean value: ```cpp bool even(int num) { return num % 2 == 0; } ``` With these implementations, the `even` function checks if the input integer is even and returns the corresponding boolean value.