Question

include using namespace std; void cheers(int n); int main( ) { cheers(3); return 0; } void cheers(int n) { if (n… # What is the output of the following program? #include using namespace std; void cheers(int n); int main( ) { cheers(3); return 0; } void cheers(int n) { if (n == 1) { cout << "Hurray\n"; } else { cout << "Hip "; cheers(n ? 1); } }

Short answer

Answer: The output of the given C++ program is "Hip Hip Hurray\n".

Step-by-step solution

Identify the Base Case

We'll start by identifying the base case of the recursive function "cheers()". If the input 'n' is equal to 1, the function will print "Hurray\n".

Analyze the Recursion

If the input 'n' is not equal to 1, the function will print "Hip " and then call itself with the input decreased by one (cheers(n-1)).

Methodically Process the Recursive Calls

Here is the sequence of function calls step by step: 1. cheers(3) is called in the main() function: - Since 3 != 1, prints "Hip ", then calls cheers(2) 2. cheers(2) is called: - Since 2 != 1, prints "Hip ", then calls cheers(1) 3. cheers(1) is called: - Since 1 == 1, prints "Hurray\n"

Combine the Outputs

By combining the outputs from each level of the recursive call, we can determine the final output: "Hip Hip Hurray\n" So, the output of the given program will be: Hip Hip Hurray