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Question: Determine the sub transient fault current in per-unit and in kA during a bolted three-phase fault at the fault bus selected in Problem 9.2.

Short Answer

Expert verified

Answer

The sub transient fault current in per unit and kA are9.363<9009.363<15009.363<300pu and7.067<-9007.067<-15007.067<-300 respectively.

Step by step solution

01

Write the given data from the question

Write the rating of the generators.

The power rating of generator is G1 1000 MVA, the voltage rating is 15 KV, the reactance Xd''and X0 are equal to 0.18 per unit , and the value of X0 is 0.07 per unit.

The power rating of generator is G2 1000 MVA, the voltage rating is 15 KV, the reactance Xd''and X0 are equal to 0.20 per unit , and the value of X0 is 0.10 per unit.

.The power rating of generator is G3 500 MVA, the voltage rating is 13.8 KV, the reactance Xd''and X0 al to 0.18 per unit , and the value of X0 is 0.05 per unit.

.

The power rating of generator is G4 750 MVA, the voltage rating is 15 KV, the reactance Xd'' i s 0.30 and X2 is 0.40 per unit , and the value of X0 is 0.10 per unit.

Write the rating of the transformer.

The power rating of transformer T1 is 1000 MVA, the voltage rating is , and the value of is .

The power rating of transformer is , the voltage rating is, and the value of is .

The power rating of transformer is , the voltage rating is, and the value of is .

The power rating of transformer is , the voltage rating is, and the value of is .

Write the rating of transmission.

The voltage rating of transmission line is , reactance is , and is .

The voltage rating of transmission line is , reactance is , and is .

The voltage rating of transmission line is , reactance is , and is .

The neutral reactance of the generator 3, .

The base MVA, .

The base voltage, .

The pre fault voltage, .

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Most popular questions from this chapter

Faults at bus n in Problem 9.8 are of interest (the instructor selects , or ). Determine the Thevenin equivalent of each sequence network as viewed from the fault bus. Prefault voltage is 1.0 per unit. Prefault load currents and Dโ€“Y phase shifts are neglected.

The single-line diagram of a three-phase power system is shown in Figure 9.17. Equipment ratings are given as follows:

Synchronous generators:

G1โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰1000โ€‰MVAโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰15โ€‰kVโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰X''d=X2=0.18,X0=0.07โ€‰perโ€‰unitโ€‰โ€‰G2โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰1000โ€‰MVAโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰15โ€‰kVโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰X''d=X2=0.20,X0=0.10โ€‰perโ€‰unitโ€‰โ€‰G3โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰500โ€‰MVAโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰13.8โ€‰kVโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰X''d=X2=0.1507,X0=0.05โ€‰perโ€‰unitโ€‰G4โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰750โ€‰MVAโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰13.8โ€‰kVโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰X''d=0.30,X2=0.40,X0=0.10โ€‰perโ€‰unitโ€‰โ€‰โ€‰

Transformers:

T1โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰1000โ€‰MVAโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰15โ€‰kVโ€‰ฮ”/765โ€‰kVโ€‰Yโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰X0=0.10โ€‰perโ€‰unitโ€‰T2โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰1000โ€‰MVAโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰15โ€‰kVโ€‰ฮ”/765โ€‰kVโ€‰Yโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰X0=0.10โ€‰perโ€‰unitโ€‰โ€‰T3โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰500โ€‰MVAโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰15โ€‰kVโ€‰ฮ”/765โ€‰kVโ€‰Yโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰X0=0.12โ€‰perโ€‰unitT4โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰750โ€‰MVAโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰15โ€‰kVโ€‰ฮ”/765โ€‰kVโ€‰Yโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰X0=0.111โ€‰perโ€‰unit

Transmission line:

1-2โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰765โ€‰kVโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰X1=50โ€‰ฮฉ,โ€‰โ€‰X0=150โ€‰ฮฉ1-3โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰765โ€‰kVโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰X1=40โ€‰ฮฉ,โ€‰โ€‰X0=100โ€‰ฮฉ2-3โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰765โ€‰kVโ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰โ€‰X1=40โ€‰ฮฉ,โ€‰โ€‰X0=100โ€‰ฮฉ

The inductor connected to Generator 3 neutral has a reactance of0.05โ€‰perโ€‰unit using generator 3 ratings as a base. Draw the zero-, positive-, and negative-sequence reactance diagrams using a1000โˆ’MVA,765โˆ’kV base in the zone of line 1โ€“2. Neglect theฮ”-Y transformer phase shifts.

Question: In Problem 9.1 and Figure 9.17, let be replaced by , keeping the rest of the data to be the same. Repeat (a) Problems 9.1, (b) 9.2, and (c) 9.3.


Repeat Problem 9.38 for a bolted single line-to-ground fault at bus 1.

For the system of Problem 9.12, compute the fault current and voltages at the fault for the following faults at bus 3: (a) a bolted single line-to ground fault, (b) a bolted line-to-line fault, (c) a bolted double line-to ground fault. Also, for the single line-to-ground fault at bus 3, determine the currents and voltages at the terminals of generators G1 and G2.

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