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At the general three-phase bus shown in Figure 9.7(a) of the text, consider a simultaneous single line-to-ground fault on phase a and line-to-line fault between phases b and c, with no fault impedances. Obtain the sequence-network interconnection satisfying the current and voltage constraints.

Short Answer

Expert verified

The sequential network for currents is shown below.

The sequential network for voltages is shown below.

Step by step solution

01

write the given data from the question.

The single line to ground fault on phasea .

Line to line fault between phase b and c.

02

Determine the sequence-network interconnection satisfying the current and voltage constraints.

The equation to calculate the sequence current is given as follows,

[I0I1I2]=13[1111a2a1aa2][IaIbIc] …… (1)

Here, role="math" localid="1655881375695" I0, I1, I2 are the sequence current and Ia,Ib,Ic are the phase current.

The equation to calculate the sequence voltage is given as follows,

role="math" localid="1655881512153" [V0V1V2]=13[1111a2a1aa2][VaVbVc] …… (2)

Here, V0,V1,V2are the sequence voltages and Va,Vb,Vc are the phase voltages.

03

Determine the sequence-network interconnection satisfying the current and voltage constraints.

Consider the schematic diagram of the system with single line ground fault on phasea and line to line fault on phaseb andc .

The fault conditions from the above,

Va=0Vb=VcIb+Ic=0Ib=Ic

Calculate the relationship between sequence current and phase currents.

SubstituteIb forIc into equation (1).

I0I1I2=131111a2a1aa2IaIbIbI0I1I2=13Ia+IbIbIa+a2IbaIbIa+aIba2IbI0I1I2=13IaIa+(a2a)IbIa+(aa2)Ib

The sequential network that satisfy the above equations.

Calculate the relationship between sequence voltages and phase voltages.

SubstituteVb forVC into equation (2).

V0V1V2=131111a2a1aa20VbVbV0V1V2=130+Vb+Vb(a2+a)Vb(a2+a)VbV0V1V2=132VbVbVb

The sequential network that satisfy the above equations.

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Most popular questions from this chapter

Question:For the system of Problem 9.11, compute the fault current and voltages at the fault for the following faults at point F: (a) a bolted single line-to-ground fault; (b) a line-to-line fault through a fault impedance ZF =j0.05; (c) a double line-to-ground fault from phase B to C to ground, where phase B has a fault impedance ZF =j0.05 , phase C also has a fault impedance ZF =j0.05, and the common line-to-ground fault impedance is ZG =j0.033 per unit.

The venin equivalent sequence networks looking into the faulted bus of a power system are given with Z1=j0.15 ,Z2=j0.15 ,Z0=j0.2 andE1=10, per unit. Compute the fault currents and voltages for the following faults occurring at the faulted bus:

(a) Balanced three-phase fault

(b) Single line-to-ground fault

(c) Line-line fault

(d) Double line-to-ground fault. Which is the worst fault from the viewpoint of the fault current?

What is the “three-position” scheme for MV switchgear? Describe the interlocking of the three positions.

Consider the one line diagram of a simple power system shown in Figure 9.20. System data in per-unit on a 100MVAbase are given as follows:

Synchronous generators:

G1              100MVA              20kV               X1=X2=0.15                  X0=0.05G2              100MVA             20kV              X1=X2=0.15                  X0=0.05

Transformers:

T1                     100MVA            20/220kV            X1=X2=X0=0.1aT2                     100MVA            20/220kV            X1=X2=X0=0.1

Transmission lines:

L12               100MVA         220kV      X1=X2=0.125                X0=0.3L13               100MVA         220kV      X1=X2=0.15                X0=0.35L23               100MVA         220kV      X1=X2=0.25                X0=0.7125

The neutral of each generator is grounded through a current-limiting reactor of æ 0.08333 per unit on a100MVA base. All transformer neutrals are solidly grounded. The generators are operating no-load at their rated voltages and rated frequency with their EMFs in phase. Determine the fault current for a balanced three-phase fault at bus 3 through a fault impedance ZF=0.1per unit on a100MVA base. Neglect Δ-Yphase shifts.

Question:For a line-to-line fault with a fault impedance ZF, the positive-and negative-sequence networks are to be connected ________ at the fault terminals through the impedance of times ; the zero-sequence current is ________.

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