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Find the inductive reactance per mile of a single-phase overhead transmission line at 60Hz given the conductors to be Partridge and the spacing between centers to be 30ft .

Short Answer

Expert verified

The inductive reactance per mile is1.75mi.

Step by step solution

01

Write the given data by the question.

The spacing between the conductors D=30ft.

The frequency of the system f=60Hz.

The GMR at 60Hz for code word Partridge is 0.0217ft.

GMR=0.0217ft

02

Determine the formulas to calculate the inductive reactance per mile of single-phase overhead transmission line.

The expression to calculate the overhead transmission line inductance is given by,

L=4×10-7InDGMR

…… (1)

The expression to calculate overhead transmission line inductive reactance is given by,

…… (2)

03

Determine the inductive reactance of the overhead transmission line.

Calculate the inductance of the overhead transmission line.

Substitute 30ft for D and 0.0217ft for GMR into equation (1).

Calculate the inductive reactance of the overhead transmission line.

Substituteforandforinto equation (2).

Calculate inductive reactance of the overhead transmission line in ohms per miles.

Hence inductive reactance per mile is.

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Most popular questions from this chapter

Question: Does bundling reduce the series reactance of the line?

(a) Yes (b) No

(a) In practice, one deals with the inductive reactance of the line per phase per mile and use the logarithm to the base 10. Show that Eq. (4.5.9) of the text can be rewritten as

x=klogDr'ohmspermilephase=xd+xa

Where,Xd=klogD is the inductive reactance spacing factor in ohms per mile

Xa=klog1r' is the inductive reactance at 1 ft spacing in Ohm’s mile per mile

k=4.657×10-3f=0.2794at 60Hz

(b) Determine the inductive reactance mile per phase at 60 Hz for a single-phase line with phase separation of 10 ft and conductor radius of 0.06677 ft. If the spacing is doubled, how does the reactance change?

Question:Match the following for the current distribution throughout the conductor cross section:

(i) For dc (a) uniform

(ii) For ac (b) nonuniform

Figure 4.34 shows double circuit conductors' relative positions in segment of transposition of a completely transposed three-phase overhead transmission line. The inductance is given by
L=2×10-7InGMDGMHm.phase

Wherelocalid="1655281435587" GMD=(DABeqDBCeqDCAeq)13

With mean distances defined by equivalent spacings


localid="1655281441455" DABeq=(D12D1'2'D12'D1'2)14DBCeq=(D23D2'3'D2'3D23')14DCAeq=(D13D1'3'D13'D1'3)14

And localid="1655281446162" GMR=[(GMR)A(GMR)B(GMR)C]13(GMR)A=[r'D11']12;(GMR)B[r'D22']12;(GMR)C=[r'D33']12;with phase GMRs defined by

andr'is the GMR of the phase conductor.

Now consider alocalid="1655281454241" 345kV, three-phase double-circuit line with phase-conductor’s GMR oflocalid="1655281463304" 0.0588ftand the horizontal conductor configuration shown in figure 4.35.


(a) Determine the inductance per meter per phase in Henries(H).

(b) Calculate the inductance of just one circuit and then divide by 2 to obtain the inductance of the double circuit.

Rework Problem 4.41 if the bundled line has (a) three ACSR,1351kcmilconductors per phase or (b) three ACSR, 900kcmilconductors per phase without changing the bundle spacing or the phase spacings between bundle centers.

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