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Match the following.

(i) Hysteresis loss,

(a) Can be reduced by constructing the core with laminated sheets of the alloy steel

(ii) Eddy current loss,

(b) Can be reduced by the use of special high grades of alloy steel as core material.

Short Answer

Expert verified
  1. The correct match for (i) is (b).
  2. The correct match for (ii) is (a).

Step by step solution

01

Define the iron losses in transformer.

In transformer, there are losses such as iron/core losses, copper/ohmic losses, stray losses and dielectric losses.

The iron losses are further categorized as hysteresis losses and eddy current losses.

Pi=Pe+Ph ……. (1)

Here, Piis iron loss, Peis eddy current loss and Phis hysteresis loss.

02

Explanation for minimizing the eddy current loss.

To reduce the eddy current loss Pein a transformer, the laminated sheets are used in a core using steel alloy and then it is stamped. The thickness of this laminations is in millimeter. But, it should not be much thin, otherwise the lamination may breakdown.

03

Explanation for minimizing the hysteresis loss.

To reduce the hysteresis loss Phin a transformer, the laminated sheets cannot be used, because hysteresis loss is more related to the magnetic material.

To reduce the hysteresis loss, the special high grade alloy steel must be used.

Therefore, the correct match for (i) is (b) and the correct match for (ii) is (a).

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Most popular questions from this chapter

A single-phase step-down transformer is rated 13MVA,66kV11.5kV. With the 11.5kVwinding short-circuited, rated current flows when the voltage applied to the primary is 5.5kV. The power input is read as 100 kW. DetermineReq1andXeq1 in ohms referred to the high-voltage winding.

The ratings of a three-phase, three-winding transformer are

Primary: Yconnected,66kV,15MVA

Secondary: Yconnected,13.2kV,10MVA

Tertiary: Δ connected,2.3kV,5MVA

Neglecting resistances and exciting current, the leakage reactance’s are:

XPS=0.09per unit on a15MVA,66kVbase

XPT=0.08per unit on a15MVA,66kVbase

XST=0.05per unit on a 10MVA,13.2kVbase

Determine the reactance’s of the per-phase equivalent circuitusing a base of 15MVA,and66kV for the primary.

Reconsider Problem 3.64 with the change that now Tbincludes both a transformer of the same turns ratio as Taand a regulating transformer with a4° phase shift. On the base ofTa the impedance of the two components of Tbper unit. Determine the complex power in per unit transmitted to the load through each transformer. Comment on how the transformers share the real and reactive powers.

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Generator 1:1000MVA,18kV,X''=0.2pu .

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T1,T2,T3, T4, :

Three-phase Y–Y transformerT5: 1500MVA, 500kV/20kV, X=0.1pu

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