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The per-unit quantity is always dimensionless.

(a) True

(b) False

Short Answer

Expert verified

Therefore, the correct option is (a) True

Step by step solution

01

Define the formulas of per-unit impedance.

Write the formula of per-unit impedance.

Zp.u=ZohmZbase ……. (1)

Here, Zp.uis a per-unit value of impedance, Zohm is a real value of impedance, and is a base value of impedance.

02

Determine the unit of per-unit impedance.

From equation (1),the real value of impedance Zohm has a unit ohm and the base value of impedance Zbase also has a unit ohm. So, by equation (1), the unit gets cancelled and Zp.u becomes dimensionless.

This is true for per-unit currents, voltages and power.

Therefore, option (a) True is correct.

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Most popular questions from this chapter

Consider the equivalent circuit of figure3.10(c)in the text. After neglecting the winding resistances and exciting current, could x1,x2,x3becomes negative, even though the leakage reactance are always positive.

(a) Yes

(b) No

A low value of transformer leakage reactance is desired to minimize the voltage drop, but a high value is desired to limit the fault current, thereby leading to a compromise in the design specification.

(a) True

(b) False

In developing per-unit circuits of systems such as the one shown in Figure 3.10, When moving across a transformer, the voltage base is changed in proportion to the transformer voltage ratings.

(a) True (b) False

A three-phase transformer is rated 1000MVA,220Y/22ΔkV. The Y-equivalent short-circuit impedance, considered equal to the leakage reactance, measured on the low-voltage side is0.1Ω.Compute the per-unit reactance of the transformer. In a system in which the base on the high-voltage side of the transformer is100MVA,230kV, what value of the per-unit reactance should be used to represent this transformer?

Figure 3.32 shows the one line diagram of a three-phase power system. By selecting a common base of100MVAand22kVon the generator side, draw an impedance diagram showing all impedances including the load impedance in per-unit. The data are given as follows:

G: 90MVA 22kV x=0.18pu

T1:50MVA 22kV/220kV x=0.1pu

T2:40MVA 220kV/11kV x=0.06pu

T3:40MVA localid="1655975246589" 22kV/110kV x=0.064pu

T4:40MVA 110 kV/11kV x=0.08pu

M: 66.5 MVA 10.45kV x=0.185pu

Lines 1 and 2 have series reactane of48.4Ωand65.43Ω,respectively. At bus 4, the three-phase load absorbs57MVAat10.45kVand0.6power factor lagging.

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