Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What are the advantages of secondary networks? Name two disadvantages.

Short Answer

Expert verified

Answer

Advantages and disadvantages are listed below.

Step by step solution

01

Define secondary network

The underground secondary network is simultaneously supplied by two or more primary feeders through network transformers. In order for a network to function even when two primary feeders are out of service, most networks are made of three or more primary feeders and spare transformer capacity.

02

Write the advantages of secondary networks

Following are the advantages of secondary networks:

  1. Secondary networks maintain a high standard of operating flexibility and service reliability.

  2. When the primary supply fails or is shut off, customers are not affected by outages on secondary networks.

  3. Because consumers are fed through parallel channels from the secondary mains, failures of secondary cables do not cause customer outages.

  4. The secondary network has significant voltage drop and is built to distribute the load among transformers equally. Consequently, they prevent transformer overloading.

03

Write the dis-advantages of secondary networks

  1. It is expensive.

  2. It is used in high load areas where revenues justify grid costs.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: As shown in Figure 14.24, an urban distribution substation has one 30-MVA (FOA) and three 33.3 MVA (FOA), 138 kVD/12.5 kV Y transformers denoted TR1-TR4, which feed through circuit breakers to a ring bus. The transformers are older transformers designed for 55ยฐC temperature rise.

The ring bus contains eight bus-tie circuit breakers, two of which are normally open (NO), so as to separate the ring bus into two sections. TR1 and TR2 feed one section, and TR3 and TR4 feed the other section. Also, four capacitor banks, three banks rated at 6 Mvar and one at 9 Mvar, are connected to the ring bus. Twenty-four 12.5-kV underground primary feeders are served from the substation, 12 from each section. The utility that owns this substation has the following transformer summer loading criteria based on a percentage of nameplate rating:

a. 120% for normal summer loading.

b. 150% during a two-hour emergency.

c. 130% 30-day emergency loading.

Determine the following summer ratings of this substation: (a) the normal summer rating with all four transformers in service; (b) the allowable substation rating assuming the single-contingency loss of one transformer; and (c) the 30-day emergency rating under the single-contingency loss of one transformer. Assume that during a two-hour emergency, switching can be performed to reduce the total substation load by 10% and to approximately balance the loadings of the three transformers remaining in service. Assume a 5% reduction for unequal transformer loadings.

A three-phase 138kVฮ”13.8kVY distribution substationtransformer rated 400MVAOA50MVAFA65MVAFOA has an 9%impedance. (a) Determine the rated current on the primary distribution side ofthe transformer at its OA, FA, and FOA ratings. (b) Determine the per-unittransformer impedance using a system base of 100MVA and 13.8kV on theprimary distribution side of the transformer. (c) Calculate the short-circuitcurrent on the primary distribution side of the transformer for a three-phasebolted fault on the primary distribution side. Assume that the prefault voltageis 13.8kV .

Rework Example 14.3 with RL=40ฮฉphase, XL=60ฮฉphase, and data-custom-editor="chemistry" XC=20ฮฉphase.

(a) How many Mvars of shunt capacitors are required to increase the power factor on a 10 MVA load from 0.85 to 0.9 lagging? (b) How manyMvars of shunt capacitors are required to increase the power factor on a 10 MVA load from 0.90 to 0.95 lagging? (c) Which requires more reactive power, improving a low power-factor load or a high power-factor load?

Do DER installations reduce distribution losses? If so, why?

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free