Question

For the circuit shown in Figure 2.24, compute the voltage across the load terminals.

Short answer

Therefore, the value of the load voltage is $117.88\angle (-14.{74}^0)\mathrm{V}$.

Step-by-step solution

Define the concept of KVL.

Consider the KVL equation shows that voltage drops in a circuit when summed up equals zero.

To obtain KVL equation consider a current either in the clockwise or counterclockwise direction and write the voltage drops such that if current enter negative side of the element then voltage drop is negative otherwise positive.

Determine the load voltage across the terminal.

Apply KVL to the circuit.

$-120\angle 0°+(0.1+\mathrm{j}0.5)(60\angle 0°)+¯{\mathrm{V}}_{\mathrm{Load}}=0$

Rewrite the equation in the term of ${\overline{\mathrm{V}}}_{\mathrm{Load}}$.

role="math" localid="1655117696027" $$\begin{gathered} {\overline{\mathrm{V}}}_{\mathrm{Load}}=120\angle 0°+(0.1+\mathrm{j}0.5)(60\angle 0°) \\ =114-\mathrm{j}30 \\ =117.88\angle (-14.{74}^0)\mathrm{V} \end{gathered}$$

Therefore, the value of the load voltage is$117.88\angle (-14.{74}^0)\mathrm{V}$ .