Question

For a purely capacitive circuit, with sinusoidal-steady-state excitation, the voltage and current phasors are

(a) In phase

(b) Perpendicular with each other with $\mathit{V}$ leading $\mathit{I}$

c) Perpendicular with each other with $\mathit{I}$ leading $\mathit{V}$

Short answer

Answer

Therefore the correct option is (c) : perpendicular with each other with $I$ leading$V$ .

Step-by-step solution

Use theory of AC circuit for pure capacitive load

For a pure capacitive load, the current into the load is in perpendicular with the load voltage, where current lead voltage by $\mathbf{90}\mathbf{°}$ .

Thus the correct option is (c).

Explanation for option (a)

For a pure resistive load, the current into the load is in phase with the load voltage.

Wheras for a pure capacitive load, the current into the load is in perpendicular with the load voltage, where current lead voltage by $90°$.

Thus the (a) is incorrect option.

Explanation for option (b)

For a pure inductive load, the voltage into the load is in perpendicular with the load current, where voltage lead current by $90°$.

Wheras for a pure capacitive load, the current into the load is perpendicular with the load voltage, where current lead voltage by$90°$.

Thus the (b) is incorrect option.