Question

For a purely inductive circuit, with sinusoidal-steady-state excitation, the voltage and current phasors are

(a) In phase

(b) Perpendicular with each other with $\mathit{V}$leading role="math" localid="1652441917385" $\mathit{I}$

c) Perpendicular with each other with $\mathit{I}$leading$\mathit{V}$

Short answer

Answer

Therefore the correct option is (b) : perpendicular with each other with$V$ leading $I$.

Step-by-step solution

Use theory of AC circuit for pure inductive load

For a pure inductive load, the voltage into the load is in perpendicular with the load current, where voltage lead current in phase by $\mathbf{90}\mathbf{°}$ .

Thus the correct option is (b).

Explanation for option (a)

For a pure resistive load, the current into the load is in phase with the load voltage.

Wheras for a pure inductive load, the voltage across the load is in perpendicular with the load current, where voltage lead current in phase by $90°$.

Thus the (a) is incorrect option.

Explanation for option (c)

For a pure capactive load, the voltage into the load is in perpendicular with the load current, where voltage lag current in phase by $90°$.

Thus the (c) is incorrect option.