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Consider the load convention that is used for the RLC elements shown in Figure 2.2 of the text

A. If one says that an inductor absorbs zero real power and positive reactive power, is it

(a) True

(b) False

B. If one says that a capacitor absorbs zero real power and negative reactive power (or delivers positive reactive power), is it

(a) False

(b) True

C. If one says that a (positive valued) resistor absorbs (positive) real power and zero reactive power, is it

(a) True

(b) False

Short Answer

Expert verified

Answer

A. The correct option is (a) True

B. The correct option is (b) True

C. The correct option is (a) True

Step by step solution

01

Draw the impedance and power triangles for RL and RC series circuits.

Consider that the R is a resistance, XLis inductive reactance, XC is capacitive reactance, Z is impedance and Iis a current through the series RL and series RC circuits.

Draw the impedance and power triangles for series RL circuits

Figure 1: impedance and power triangle of series RL circuit

Draw the impedance and power triangles for series RC circuits

Figure 2: impedance and power triangle of series RC circuit

02

Solution for subpart A.

From power triangle of Figure 1, the total power is given by

PTotal=I2R+jI2XL=P+jQ

Here, Pis a real power and Qis a reactive power.

From impedance diagram of Figure 1, it is clear that the inductor absorbs reactive power and zero real power.

Thus the option (a) true is correct.

03

Solution for subpart B.

From power triangle of Figure 2, the total power is given by

PTotal=I2R+jI2XL=P+jQ

Here,Pis a real power andQis a reactive power.

From impedance diagram of Figure 2, it is clear that the capacitor absorbs negative reactive power and zero real power.

Thus the option (b) true is correct.

04

Solution for subpart C.

C. From power triangle of Figure 1 and Figure 2, the real power is align to the x-axis.

From impedance diagram of Figure 1 and Figure 2, it is clear that the resistor only absorbs the real power.

Thus, the option true (a) true is correct.

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Most popular questions from this chapter

(a) Given the circuit diagram in Figure 2.32 showing admittances and current sources at nodes 3 and 4, set up the nodal equations in matrix format. (b) If the parameters are given by :Ya=-j0.8S,Yb=-j4.0S,Yc=-j4.0S,Yd=-j8.0S,Ye=-j5.0S,Yf=-j2.5S,Yg=-j0.8S,l3=1.0โˆ -90ยฐAandl4=0.62โˆ -135ยฐA,set up the nodal equations and suggest how you would go about solving for the voltages at the nodes.

Image Caption

For a purely inductive circuit, with sinusoidal-steady-state excitation, the voltage and current phasors are

(a) In phase

(b) Perpendicular with each other with Vleading role="math" localid="1652441917385" I

c) Perpendicular with each other with IleadingV

One advantage of balanced three-phase system over separate single- phase system is reduced capital and operating costs of transmission and distribution.

(a) True

(b) False

With generator convention, where the current leaves the positive terminal of the circuit element, if P is positive then positive real power is delivered.

(a) False

(b) True

A single-phase, 120V(rms),60Hzsource supplies power to a series R-L circuit consisting ofR=10ฮฉandL=40mH(a) Determine the power factor of the circuit and State whether it is lagging or leading. (b) Determine the real and reactive power absorbed by the load. (c) Calculate the peak magnetic energyWintstored in the inductor by using the expressionWint=L(lrms2)and check whether the reactive powerQ=ฯ‰Wintis satisfied. (Note: The instantaneous magnetic energy storage fluctuates between zero and the peak energy. This energy must be sent twice each cycle to the load from the source by means of reactive power flows.)

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