Question

With load convention, where the current enters the positive terminal of the circuit element, if $\mathbf{\Omega }$ is positive then positive reactive power is absorbed.

(a) True

(b) False

Short answer

Answer

Therefore, the correct option is (a) True

Step-by-step solution

Define the reactive power absorbed by an inductor

Consider that the$Q$ is a reactive power aborbed an inductor,${\mathrm{V}}_{\mathrm{rms}}$ is a voltage across inductor, ${\mathrm{I}}_{\mathrm{rms}}$is a current through inductor and $\theta$ is a power angle.

$\mathbf{Q}\mathbf{=}{\mathbf{V}}_{\mathbf{rms}}\mathbf{}{\mathbf{I}}_{\mathbf{rms}}\mathbf{}\mathbf{sin\theta }$ ……. (1)

Determine the current convention

From equation (1), it is clear that the rms current$I_{rms}$ is positive and according to the convention, this is the current entering the inductor positive terminal.

Now,$\Omega$ is a unit of inductive reactance and it will be always positive.

Hence, when current is entering the positive terminal of load, it absorbes the reactive power.

Thus the option (a) is correct.