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Let \(R\) be a ring (commutative, with 1 ) and \(f, g \in R[x, y]\), and assume that \(f\) and \(g\) have degrees less than \(m\) in \(y\) and less than \(n\) in \(x\). Let \(h=f \cdot g\). (i) Using classical univariate polynomial multiplication and viewing \(R[x, y]\) as \(R[y][x]\), bound the number of arithmetic operations in \(R\) to compute \(h\). (ii) Using Karatsuba's algorithm bound the number of operations in \(R\) to compute \(h\). (iii) Generalize parts (i) and (ii) to polynomials in an arbitrary number of variables.

Short Answer

Expert verified
(i) Classical multiplication: \( O(n^2m^2) \). (ii) Karatsuba: \( O(n^{1.585}m^{1.585}) \). (iii) General bounds: Classical \( O(d^{2v}) \), Karatsuba \( O(d^{v \log_2 3}) \).

Step by step solution

01

Analyze the Structure of Ring Polynomials

Let's first understand that we have a polynomial ring \( R[x, y] \), where \( R \) is a commutative ring with identity. The polynomials \( f \) and \( g \) have degrees less than \( m \) in \( y \) and degrees less than \( n \) in \( x \). This implies that both polynomials can be expressed as sums of terms like \( a_{i,j}x^iy^j \) where \( a_{i,j} \in R \), and \( 0 \leq i < n \), \( 0 \leq j < m \).
02

Set Up Univariate Polynomial Multiplication

Assume \( R[x, y] = R[y][x] \). Consider \( f, g \) as polynomials in \( x \) with coefficients that are polynomials in \( y \). The multiplication of two univariate polynomials of degree \( < n \) each takes \( O(n^2) \) operations using classical multiplication.
03

Calculate Operations in Terms of Coefficients

Since the coefficients are polynomials in \( y \) of degree less than \( m \), each coefficient multiplication for a given \( x \) term involves univariate polynomial multiplication in \( y \), costing \( O(m^2) \) operations. Hence, a total of \( O(n^2 \cdot m^2) \) operations in \( R \) are required.
04

Introduce Karatsuba Multiplication Algorithm

Karatsuba's algorithm helps reduce the multiplication complexity of two polynomials. For polynomials of degree \( n \), Karatsuba reduces it from \( O(n^2) \) to \( O(n^{\log_2 3}) \), which is approximately \( O(n^{1.585}) \).
05

Apply Karatsuba to Multivariable Case

The use of Karatsuba's algorithm affects both dimensions. Multiply the polynomials in \( x \) involves approximately \( O(n^{1.585}) \) operations, and multiplying the coefficients (polynomials in \( y \)) takes \( O(m^{1.585}) \). Therefore, the total number of operations is \( O(m^{1.585} \cdot n^{1.585}) \).
06

Generalization to Arbitrary Number of Variables

For polynomials in an arbitrary number of variables, assume polynomials in \( v \) variables, each having maximum degree \( d \). Using classical methods, the multiplication requires \( O(d^{2v}) \) operations. With Karatsuba's method, it reduces approximately to \( O(d^{v \log_2 3}) \). The complexity increases exponentially with the number of variables and degree of the polynomials.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ring Theory
To dive into Ring Theory, we start with basic concepts related to mathematical rings. A ring is a set equipped with two operations: addition and multiplication, which generalize the arithmetic of integers. Rings must be closed under these operations, have an additive identity (0), and every element must have an additive inverse (negative). If a ring is commutative, multiplication is commutative.
  • In our exercise, we consider a polynomial ring \( R[x, y] \), where \( R \) is a commutative ring.
  • Such polynomials have coefficients in \( R \) and involve variables, here \( x \) and \( y \).
  • Each polynomial can be seen as a sum of terms \( a_{i,j} x^i y^j \) where \( a_{i,j} \in R \).
In simpler terms, these polynomials are like traditional algebraic expressions where the coefficients are numbers from a specific ring. Understanding the structure of these polynomials helps us to carry out operations like addition and multiplication within this structured setting.
Karatsuba Algorithm
The Karatsuba Algorithm is a method that drastically reduces the number of steps required to multiply two large numbers or polynomials. Invented by Anatolii Alexeevitch Karatsuba in 1960, this algorithm uses a divide-and-conquer approach.
  • It improves multiplication complexity from the classical \( O(n^2) \) to \( O(n^{\log_2 3}) \), approximately \( O(n^{1.585}) \).
  • This gain is achieved by reducing the problem into smaller parts and recursively solving each part.
For polynomials, consider splitting a polynomial of degree \( n \) into smaller parts. Karatsuba leverages the relation:
If \( a(x) = a_1x^{m} + a_0 \) and \( b(x) = b_1x^{m} + b_0 \), then
  • Compute \( a_1b_1 \), \( a_0b_0 \), and \((a_1+a_0)(b_1+b_0) \).
  • With these steps, reconstruct \( a(x) \times b(x) \) by careful combination.
This algorithm is used extensively for efficiency, especially when dealing with polynomials of high degree.
Complexity Analysis
In complexity analysis, we study how the execution time or space requirements of an algorithm scale with the input size. Understanding this helps in designing efficient algorithms.
For polynomial multiplication:
  • Classical algorithms require \( O(n^2) \) operations for degree \( n \) polynomials.
  • Karatsuba improves it to \( O(n^{1.585}) \) by using strategic splitting.
When extended to multivariate cases (polynomials with multiple variables), the complexity can grow rapidly due to interdependence of variables.
  • In the exercise, multiplying polynomials in two variables \( x, y \) resulted in \( O(n^2 \, m^2) \) operations using classical methods.
  • Karatsuba reduces this to approximately \( O(n^{1.585} \, m^{1.585}) \).
The challenge exponentially increases with more variables because the relationships between variables add layers of computation. Thus, complexity analysis is essential for predicting performance and efficiency of algorithms.

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Most popular questions from this chapter

Let \(F=\mathbb{F}_{41}\). (i) Prove that \(\omega=14 \in F\) is a primitive 8th root of unity. Compute all powers of \(\omega\), and mark the ones that are primitive 8 th roots of unity. (ii) Let \(\eta=\omega^{2}\), and \(f=x^{7}+2 x^{6}+3 x^{4}+2 x+6 \in F[x]\). Give an explicit calculation of \(\alpha=\) \(\mathrm{DFT}_{\omega}(f)\), using the FFT. You only have to do one recursive step, and then can use direct evaluation at powers of \(\eta\). (iii) Let \(g=x^{7}+12 x^{5}+35^{3}+1 \in F[x]\). Compute \(\beta=\operatorname{DFT}_{\omega}(g), \gamma=\alpha \cdot \beta\) with coordinate-wise product, and \(h=\mathrm{DFT}_{\omega^{-1}}(\gamma)\). (iv) Compute \(f \cdot g\) in \(F[x]\) and \(f * 8 g\). Compare with your result from (iii).

(i) For all \(a \in \mathbb{F}_{19}^{\times}\), determine the powers \(a^{k}\) with \(k \mid 18\), and derive ord \((a)\) from this data only. (ii) Determine all \(n \in \mathbb{N}_{>0}\) for which \(\mathbb{F}_{19}\) contains a primitive \(n\)th root of unity, and for each such \(n\), list all primitive \(n\)th roots of unity.

Let \(p, q \in \mathbb{N}\) be distinct odd primes, \(n=p q\), and \(k, l \in \mathbb{N}\). (i) Given a primitive \(k\) th root of unity in \(\mathbb{Z}_{p}^{\times}\)and a primitive lth root of unity in \(\mathbb{Z}_{q}^{\times}\), how can you construct a primitive \(m\) th root of unity in \(\mathbb{Z}_{n}^{\times}\), where \(m=\operatorname{lcm}(k, l)\) ? (ii) Show that \(\mathbb{Z}_{n}^{\times}\)contains a primitive \(k\) th root of unity if and only if \(k \mid \operatorname{lcm}(p-1, q-1)\). (iii) Find primitive 16 th roots of unity in \(\mathbb{Z}_{17}^{\times}\)and in \(\mathbb{Z}_{97}^{\times}\), and construct a primitive 16 th root of unity in \(\mathbb{Z}_{1649}^{\times}\).

Let \(q\) be a prime power, \(\mathbb{F}_{q}\) a finite field with \(q\) elements, and \(n \in \mathbb{N}\) a divisor of \(q-1\), with prime factorization \(n=p_{1}^{e_{1}} \cdots p_{r}^{e_{r}}\). For \(a \in \mathbb{F}_{q}^{\times}\), we denote by ord \((a)\) the order of \(a\) in the multiplicative group \(\mathbb{F}_{q}^{\times}\), and want to show that ord \((a)=q-1\) for some \(a \in \mathbb{F}_{q}^{\times}\). Prove: (i) \(\operatorname{ord}(a)=n\) if and only if \(a^{n}=1\) and \(a^{n / p_{j}} \neq 1\) for \(1 \leq j \leq r\).

Show that \(\omega=x \bmod \left(x^{n}-1\right) \in R=F[x] /\left\langle x^{n}-1\right\rangle\), where \(F\) is a field of characteristic not dividing \(n\), is not a primitive \(n\)th root of unity for \(n \geq 2\).

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