Chapter 5: Problem 15
What is the least nonnegative integer \(f\) with \(f \equiv 2 \bmod 3, f \equiv 3 \bmod 5\), and \(f \equiv 2 \bmod 7\) ?
Short Answer
Expert verified
The least nonnegative integer solution is 23.
Step by step solution
01
Identify the System of Congruences
The problem gives us a system of congruences that we need to solve:\[ f \equiv 2 \mod 3 \]\[ f \equiv 3 \mod 5 \]\[ f \equiv 2 \mod 7 \]
02
Solve the First and Third Congruences Together
Notice that the first and third congruences, \( f \equiv 2 \mod 3 \) and \( f \equiv 2 \mod 7 \), can be combined. The least positive solution to these combined congruences is the least common multiple of 3 and 7 subtracting 1,Thus we look for numbers in the form:\[ f = 21k + 2 \] (since \(21 = 3 \times 7\))
03
Substitute into the Second Congruence
Substitute the expression \( f = 21k + 2 \) into the second congruence:\[ 21k + 2 \equiv 3 \mod 5 \]Simplifying, we subtract 2 from both sides:\[ 21k \equiv 1 \mod 5 \]Since \(21 \equiv 1 \mod 5\), the congruence simplifies to \(k \equiv 1 \mod 5\).
04
Solve for k
The solution for \(k \equiv 1 \mod 5\) suggests \(k = 5m + 1\) for integer \(m\). Substitute back:\[ f = 21k + 2 = 21(5m + 1) + 2 = 105m + 23 \]
05
Calculate the Least Nonnegative Integer f
To find the least nonnegative integer solution, set \(m = 0\):\[ f = 105 \times 0 + 23 = 23 \]
06
Verify the Solution
Verify that 23 satisfies all the original congruences:\( 23 \mod 3 = 2 \), \( 23 \mod 5 = 3 \), and \( 23 \mod 7 = 2 \). This confirms that 23 is correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
System of Congruences
In number theory, a system of congruences is a set of equations where each equation dictates that a certain remainder is obtained when a variable is divided by a respective divisor. These equations share a common variable. In our exercise, the system of congruences is as follows:
- \( f \equiv 2 \mod 3 \)
- \( f \equiv 3 \mod 5 \)
- \( f \equiv 2 \mod 7 \)
Chinese Remainder Theorem
The Chinese Remainder Theorem (CRT) is a powerful tool in number theory used for solving systems of congruences with different moduli. When the moduli are pairwise coprime, as they are in our problem (i.e., 3, 5, and 7 are coprime), CRT ensures us there is a unique solution modulo the product of the moduli.To apply CRT effectively, we start by combining congruences with the same remainder. Our example involves combining:
- \( f \equiv 2 \mod 3 \)
- \( f \equiv 2 \mod 7 \)
Least Common Multiple
Least Common Multiple (LCM) is used to identify the smallest multiple that two or more numbers share. When combined with congruences, it helps simplify problems by reducing equivalent congruences into a single, more manageable one.In this exercise, the LCM of 3 and 7 is calculated because both have the same remainder 2 when the variable is considered. It aids in "merging" these congruences, thus mapping their common cycle.To find the LCM, we use the formula based on their greatest common divisor (GCD):\[\text{LCM}(a, b) = \frac{|a \times b|}{\text{GCD}(a, b)}\]Here, since 3 and 7 are coprime, their LCM is simply \(3 \times 7 = 21\).With the LCM computed, our equation simplifies, revealing the merged behavior of the system: \( f \equiv 2 \mod 21 \). This relationship allows us to explore just one remainder across fewer conditions, streamlining our approach to find the solution.