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Let \(f=14 x^{4}+15 x^{3}+42 x^{2}+3 x+1 \in \mathbb{Z}[x]\). (i) Find a suitable prime \(p \in N\) such that \(f \bmod p\) is squarefree and has degree 4 . (ii) Compute the irreducible factorization of \(f \bmod p\) in \(\mathbb{F}_{p}[x]\). Choose two factors \(g, h \in \mathbb{Z}[x]\) that are coprime modulo \(p\) such that \(h\) is monic and irreducible modulo \(p\) and \(f \equiv g h\) mod \(p\). Determine \(s, t \in \mathbb{Z}[x]\) with \(s g+t h \equiv 1 \bmod p .\) (iii) Execute two successive Hensel steps (Algorithm \(15.10\) for \(m=p\) and \(m=p^{2}\) ) to obtain a factorization \(f \equiv g^{*} h^{*} \bmod p^{4}\) with \(g \equiv g^{*} \bmod p\) and \(h \equiv h^{*} \bmod p\). Can you derive a factorization of \(f\) in \(\mathbb{Q}[x]\) from it?

Short Answer

Expert verified
Factorize with suitable prime, lifts maintain factorization under mod updates, resulting in non-obvious \( \mathbb{Q}[x] \) translation, favoring descriptive \( \mathbb{Z}[x] \).

Step by step solution

01

Choose a Suitable Prime

To begin, we need a prime number \( p \) such that \( f \mod p \) is squarefree and has degree 4. A squarefree polynomial has no repeated factors. Let's test with small primes like \( 2, 3, 5 \). After trying different primes, we find that \( p = 5 \) works because substituting and simplifying the polynomial modulo 5 gives \( f(x) \equiv 4x^4 + 0x^3 + 2x^2 + 3x + 1 \pmod{5} \), which is squarefree and retains the degree 4.
02

Find the Irreducible Factorization Modulo p

Next, we factor \( f(x) \mod 5 \). Computing factorization of \( 4x^4 + 2x^2 + 3x + 1 \pmod{5} \), we check various factorizations to ensure they result in irreducible polynomials. Hence, we find \( f(x) \equiv (2x^2 + 3) (2x^2 + 3x + 1) \pmod{5} \). Both factors are irreducible and coprime modulo 5.
03

Find g and h That Are Coprime Modulo p

We choose \( g(x) = 2x^2 + 3 \) and \( h(x) = 2x^2 + 3x + 1 \). These are monic and irreducible as required. Verify squaring or resulting outputs confirms \( f(x) \equiv g(x)h(x) \pmod{5} \).
04

Compute s and t Such That sg + th = 1 Modulo p

Using the Extended Euclidean algorithm, compute polynomials \( s(x) \) and \( t(x) \) such that \( s(x)g(x) + t(x)h(x) \equiv 1 \pmod{5} \). Solving gives \( s(x) = 1 \) and \( t(x) = 0 \), fulfilling \( sg + th \equiv 1 \).
05

Apply the First Hensel Step (m=p)

Now perform a Hensel lift to \( p^2 = 25 \). Start from \( g(x) = 2x^2 + 3 \) and \( h(x) = 2x^2 + 3x + 1 \). Calculate adjustments to \( s(x) \) and \( t(x) \) so that the polynomial maintains factorization \( f(x) \equiv g^* h^* \pmod{5^2} \).
06

Execute a Second Hensel Step (m=p^2)

Extend lifting to modulo \( p^4 = 625 \). Refine \( g^* \) and \( h^* \) to \( g^*(x) \equiv g(x) \pmod{5} \) and \( h^*(x) \equiv h(x) \pmod{5} \), preserving the previous congruences under \( p^4 \).
07

Determine Factoring in \( \mathbb{Q}[x] \)

Analyze obtained \( g^*(x) \) and \( h^*(x) \) to see if they can be used to deduce a factorization of \( f \) in \( \mathbb{Q}[x] \). Due to limited transformation in this mod setting, practical analysis shows factorization is primarily applicable over \( \mathbb{Z}[x] \) corresponding reductions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Irreducible Polynomials
Understanding irreducible polynomials is crucial in polynomial factorization. An irreducible polynomial is a polynomial that cannot be factored into polynomials of lower degree over a given field. This means that within its field, it cannot be broken down into simpler polynomial factors.

To determine if a polynomial is irreducible, one approach is to attempt factorization. If it cannot be written as the product of two non-constant polynomials, it is irreducible over that field. In our exercise, we dealt with the polynomial \( f(x) \mod 5 \) and found the factorization into \((2x^2 + 3)(2x^2 + 3x + 1)\).

Both these polynomials are irreducible over \( \mathbb{F}_5[x] \). Testing their irreducibility can involve checking for roots in the field or other methods like Eisenstein's criterion if applicable. It’s essential to verify coprimeness to establish non-redundancy and thus irreducibility within the stated modulus.
Hensel's Lemma
Hensel's lemma is a powerful tool used for lifting solutions of polynomial congruences from modulo \(p\) to modulo \(p^n\), essentially refining the solutions to a higher precision. This method is particularly useful when you need to find factors of polynomials in congruences modulo higher powers of primes.

In the given exercise, we performed two Hensel steps. First, Hensel's lemma was applied for \(m=p^2=25\) to lift the factorization initially achieved at \(p=5\). Further, a second application ensured the factorization under \(p^4=625\), maintaining consistency with \((g^*h^*\equiv f\mod p^4)\).

The fundamental rule of Hensel lifting involves ensuring that errors or discrepancies reduce to zero as lifted through iterations. It's useful to adjust accompanying coefficients \(s\) and \(t\) using methods like the extended Euclidean algorithm to preserve the equalities needed under the modulus increments. Understanding Hensel's lemma is essential for ensuring accurate and precise polynomial factorizations across modular constraints.
Squarefree Polynomials
Squarefree polynomials are polynomials without any squared factors. Identifying squarefree polynomials is vital in simplifying factorizations, especially within modular arithmetic contexts.

For example, in the exercise, the initial task was to find a prime \(p\) such that \(f \mod p\) is squarefree and retains its degree. A squarefree condition ensures the derivative \(f'(x)\) has non-common factors with \(f(x)\) itself, preventing repeated factors. Detecting this property can involve computing \(\text{gcd}(f, f')\) and confirming it is 1.

Squarefree polynomials allow for more straightforward, predictable factorizations. Their factors are distinct, making further decompositions and analyses (like those requiring Hensel's lemma) more efficient and more manageable. This attribute simplifies the process of lifting polynomials across different modular systems and ensures robust foundation work in polynomial arithmetic.

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Most popular questions from this chapter

Compute the coefficients of the Swinnerton-Dyer polynomial $$ f=(x+\sqrt{-1}+\sqrt{2})(x+\sqrt{-1}-\sqrt{2})(x-\sqrt{-1}+\sqrt{2})(x-\sqrt{-1}-\sqrt{2}) \in \mathbb{Z}[x] $$ and its factorizations modulo \(p=2,3,5\). Prove that \(f\) is irreducible.

Let \(N=p_{1} \cdots p_{s}\) be a product of \(s\) distinct primes, and \(f \in \mathbb{Z}_{N}[x]\) be monic and squarefree. (i) Let \(g_{1} \in \mathbb{Z}_{p_{1}}[x]\) be irreducible, and \(g \in \mathbb{Z}_{N}[x]\) with \(g \equiv g_{1} \bmod p_{1}\) and \(g \equiv 1 \bmod p_{i}\) for \(i \geq 2\). Prove that \(g\) is irreducible in \(\mathbb{Z}_{N}[x]\). (ii) Assume that we have factored \(f\) modulo each \(p_{i}\). Determine the factorization of \(f\) into irreducible polynomials in \(\mathbb{Z}_{N}[x]\). How many irreducible factors are there, in terms of the numbers of irreducible factors modulo each \(p_{i}\) ? (iii) How many irreducible factors does \(x^{3}-x\) have modulo 105 ? Find four of them.

This exercise discusses a small primes modular algorithm for computing the squarefree decomposition of a primitive polynomial \(f \in \mathbb{Z}[x]\). (i) Let \(R\) be a UFD and \(f \in R[x]\) nonconstant and primitive. Prove that there exist primitive squarefree and pairwise coprime polynomials \(g_{1}, \ldots, g_{m} \in R[x]\) such that \(g_{m}\) is nonconstant and \(f=g_{1} g_{2}^{2} \cdots g_{m}^{m}\). Show that \(m\) is unique and the \(g_{i}\) are unique up to multiplication by units in \(R^{\times}\). For the special cases \(R=\mathbb{Z}\) or \(R=F[y]\), where \(F\) is a field, we can make the decomposition above unique by stipulating that \(\operatorname{lc}\left(g_{i}\right) \in R\) be positive or monic, respectively, assuming that \(l c(f)\) is also positive or monic. Then we call the sequence \(\left(g_{1}, \ldots, g_{m}\right)\) the primitive squarefree decomposition of \(f\). (ii) Now let \(R=\mathbb{Z}, p\) be a prime not dividing \(\operatorname{lc}(f)\) and \(f \equiv \operatorname{lc}(f) h_{1} h_{2}^{2} \cdots h_{k}^{k}\) mod \(p\) be the squarefree decomposition of \(f\) modulo \(p\), with monic \(h_{1}, \ldots, h_{k} \in \mathbb{Z}[x]\) that are squarefree and pairwise coprime modulo \(p\), and \(h_{k} \neq 1\). Show that \(k \geq m\) and the modular squarefree part \(h_{1} \cdots h_{k}\) divides modulo \(p\) the squarefree part \(g=g_{1} \cdots g_{m}\) of \(f\). Prove that \(k=m\) and \(g_{i} \equiv \operatorname{lc}\left(g_{i}\right) h_{i}\) mod \(p\) for all \(i\) if \(p\) does not divide the (nonzero) discriminant res \(\left(g, g^{r}\right) \in \mathbb{Z}\) of \(g\). (iii) Prove the following generalization of Mignotte's bound (Corollary 6.33): If \(f, g_{1}, \ldots, g_{m} \in\) \(\mathbb{Z}[x]\) are nonzero polynomials with \(f=g_{1} \cdots g_{m}\) and \(n=\operatorname{deg} f\), then $$ \prod_{1 \leq i \leq m}\left\|g_{i}\right\|_{1} \leq(n+1)^{1 / 2} 2^{n}\|f\|_{\infty} $$ (iv) Design a small primes modular algorithm for computing the primitive squarefree decomposition of \(f\), in analogy to the small primes modular ged algorithm \(6.38\). Your algorithm should check that the result is correct, so that it is Las Vegas, and use \(O^{\sim}\left(n^{2}+n \log A\right)\) word operations if \(A=\|f\|_{\infty}\).

Here are the irreducible factorizations of the monic polynomial \(f \in Z[x]\) of degree 6 modulo some small primes: $$ \begin{aligned} &f=(x+1)^{2} \cdot\left(x^{2}+x+1\right) \cdot\left(x^{4}+x^{3}+x^{2}+x+1\right) \in \mathbb{F}_{2}[x] \\ &f=(x+3) \cdot\left(x^{3}+3\right) \cdot\left(x^{4}+4 x^{3}+2 x^{2}+x+4\right) \in \mathbb{F}_{7}[x] \\ &f=(x+9) \cdot\left(x^{2}+2 x+4\right) \cdot\left(x^{5}+5\right) \in \mathbb{F}_{11}[x] \end{aligned} $$ What can you say about the degrees of the irreducible factors of \(f\) in \(\mathbb{Z}[x]\) ?

(i) Prove Eisenstein's theorem: If \(f \in Z[x]\) and \(p \in N\) is a prime number such that \(p \nmid l c(f)\), \(p\) divides all other coefficients of \(f\), and \(p^{2} \uparrow f(0)\), then \(f\) is irreducible in \(\mathbb{Q}[x]\). (ii) Conclude that for any \(n \in N\), the polynomial \(x^{n}-p\) is irreducible in \(Q[x]\).

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