Chapter 13: Problem 2
Let \(f, g: \mathbf{R} \rightarrow \mathbf{C}\) be two \(2 \pi\)-periodic signals. If \(f, g\) are sufficiently smooth, then the convolution $$ (f * g)(t)=\int_{0}^{2 \pi} f(s) g(t-s) d s $$ exists for all \(t \in R\). Prove that \(f * g\) is again \(2 \pi\)-periodic, and that the convolution property \(\widehat{f * g}=\widehat{f} \cdot \hat{g}\) holds, so that $$ (\widehat{f * g})(k)=\hat{f}(k) \cdot \bar{g}(k) \text { for all } k \in Z \text {. } $$ (Thus the Fourier Transform converts convolution into pointwise multiplication.) You may assume that all occurring integrals exist.
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