Chapter 3: Problem 1
This is a continuation of Subsection 2.4.2. Consider a satellite of unit mass in earth orbit specified by its position and velocity in polar coordinates \(r, \dot{r}, \theta, \dot{\theta} .\) The input functions are a radial thrust \(u_{1}(t)\) and a tangential thrust of \(u_{2}(t) .\) Newton's laws yield $$ \vec{r}=r \dot{\theta}^{2}-\frac{g}{r^{2}}+u_{1} ; \quad \ddot{\theta}=-\frac{2 \dot{\theta} \dot{r}}{r}+\frac{1}{r} u_{2} . $$ (Compare (2.6) and take \(m_{\mathrm{s}}=1\) and rewrite \(G m_{\mathrm{e}}\) as \(g .\) ) Show that, if \(u_{1}(t)=\) \(u_{2}(t)=0, r(t)=\sigma\) (constant), \(\theta(t)=\omega t\) ( \(\omega\) is constant) with \(\sigma^{3} \omega^{2}=g\) is a solution and that linearization around this solution leads to (with \(x_{1}=r(t)-\) \(\left.\sigma ; x_{2}=\dot{r} ; x_{3}=\sigma(\theta-\omega t) ; x_{4}=\sigma(\dot{\theta}-\omega)\right)\) $$ \frac{d x}{d t}=\left(\begin{array}{cccc} 0 & 1 & 0 & 0 \\ 3 \omega^{2} & 0 & 0 & 2 \omega \\ 0 & 0 & 0 & 1 \\ 0 & -2 \omega & 0 & 0 \end{array}\right) x+\left(\begin{array}{ll} 0 & 0 \\ 1 & 0 \\ 0 & 0 \\ 0 & 1 \end{array}\right) u $$
Short Answer
Step by step solution
Key Concepts
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