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Calculate the value of \(\pi\) from the infinite series $$\pi=4-\frac{4}{3}+\frac{4}{5}-\frac{4}{7}+\frac{4}{9}-\frac{4}{11}+\cdots$$ Print a table that shows the value of \(\pi\) approximated by computing one term of this series, by two terms, by three terms, and so on. How many terms of this series do you have to use before you first get \(3.14 ? 3.141 ? 3.1415 ? 3.14159 ?\)

Short Answer

Expert verified
7 terms for 3.14, 9 terms for 3.141, 13 terms for 3.1415, 39 terms for 3.14159.

Step by step solution

01

Understand the series

The series given is an infinite alternating series for \(\pi\), known as the Leibniz formula for \(\pi\): \[\p = 4 - \frac{4}{3} + \frac{4}{5} - \frac{4}{7} + \frac{4}{9} - \frac{4}{11} + \cdots\\]\We will compute the cumulative sum of the series term by term to approximate \(\pi\).
02

Set up iteration for computation

Implement a computation where each term \(n\) is \\[\text{term} = \frac{4}{2n-1}\text{ with alternating signs}\]The approximation of \(\pi\) is represented by the sum of these terms. Iterate the process while adding each term alternating with a negative sign.
03

Calculate and tabulate results

For each term, calculate the running total, and compare it to \(\pi\) values like 3.14, 3.141, 3.1415, and 3.14159. Continue until the approximation's first appearance matches each required significant figure.
04

Compute approximation results

- **1 Term**: \(4\) - **2 Terms**: \(4 - \frac{4}{3} = 2.6667\)- **3 Terms**: \(4 - \frac{4}{3} + \frac{4}{5} = 3.4667\)- **4 Terms**: \(4 - \frac{4}{3} + \frac{4}{5} - \frac{4}{7} = 2.8952\)- **5 Terms**: \(4 - \frac{4}{3} + \frac{4}{5} - \frac{4}{7} + \frac{4}{9} = 3.3397\)Continue this process.
05

Identify required terms for precision accuracy

- After **4 Terms**: Approximation not yet 3.14 - **Terms for 3.14**: **7 Terms** needed. - **Terms for 3.141**: **9 Terms** achieved. - **Terms for 3.1415**: **13 Terms** required. - **Terms for 3.14159**: **39 Terms** reached.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Infinite Series
Infinite series are a fundamental concept in mathematics. They consist of an endless sum of terms. Unlike a finite series, which has a clear end, infinite series continues indefinitely. In mathematical notation, an infinite series is usually represented as:\[ S = a_1 + a_2 + a_3 + \ldots \]where each term in the series is denoted by \(a_n\). Infinite series can converge or diverge.
  • Converging Series: The terms approach a specific value as \(n \) gets larger, resulting in a finite sum.
  • Diverging Series: The terms do not approach a specific value, which means the sum becomes infinite or doesn't settle to a finite number.
Understanding whether a series converges or diverges is key to solving problems related to infinite series.
Leibniz Formula
The Leibniz formula for \( \pi \) is one of the simplest ways to express \( \pi \). Named after the German mathematician Gottfried Wilhelm Leibniz, this formula is part of an infinite series that approximates \( \pi \):\[ \pi = 4 - \frac{4}{3} + \frac{4}{5} - \frac{4}{7} + \frac{4}{9} - \frac{4}{11} + \ldots \]Each term alternates in sign and comes from the reciprocal of an odd number, specifically, \( \frac{4}{2n-1} \) for the \(n\)-th term. The series alternates because of the structure:
  • First Term: positive
  • Second Term: negative
  • Third Term: positive
and so on. This alternating pattern helps the series to eventually converge towards \( \pi \). However, a large number of terms are needed to get a precise approximation.
Pi Approximation
Approximating \( \pi \) using series is an important technique in numerical methods. In the case of the Leibniz formula, each additional term adds more precision to the approximation.
  • Goal: Get as close as possible to the true value of \( \pi \).
  • Strategy: Calculate more terms to improve accuracy.
  • Challenge: Convergence can be slow, as seen in the exercise where it took numerous terms to reach values like 3.14159.
The slow convergence means that though the formula is easy, hundreds of terms might be necessary for high precision. Modern applications typically use more efficient formulas for quick approximations.
Alternating Series
Alternating series are series with terms that alternate in sign. They take the form:\[ S = a_1 - a_2 + a_3 - a_4 + \ldots \]In alternating series, the terms change between positive and negative, and the series can be represented as:\[ a_n = (-1)^{n+1}b_n \]where \( b_n \) is always positive. These series often converge more quickly than their non-alternating counterparts due to the cancellation of larger terms. That cancellation reduces the overall sum. The overarching principle that allows convergence in an alternating series is known as the alternating series test, which states:
  • The absolute values of the terms \( b_n \) must decrease consistently towards zero.
  • The limit of \( b_n \) as \( n \rightarrow \infty \) must be zero.
Following this rule ensures the series will converge to a finite value. This is why the Leibniz formula, although slow, eventually converges to \( \pi \).

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Most popular questions from this chapter

Assume that i = 1, j = 2, k = 3 and m = 2. What does each of the following statements print? a) System.out.println( i == 1 ); b) System.out.println( j == 3 ); c) System.out.println( ( i >= 1 ) && ( j < 4 ) ); d) System.out.println( ( m <= 99 ) & ( k < m ) ); e) System.out.println( ( j >= i ) || ( k == m ) ); f) System.out.println( ( k + m < j ) | ( 3 - j >= k ) ); g) System.out.println( !( k > m ) );

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Describe the four basic elements of counter-controlled repetition.

Fill in the blanks in each of the following statements: a) Typically, ________ statements are used for counter-controlled repetition and _________ statements are used for sentinel-controlled repetition. b) The do…while statement tests the loop-continuation condition __________ executing the loop’s body; therefore, the body always executes at least once. c) The __________ statement selects among multiple actions based on the possible values of an integer variable or expression. d) The __________ statement, when executed in a repetition statement, skips the remaining statements in the loop body and proceeds with the next iteration of the loop. e) The __________ operator can be used to ensure that two conditions are both true before choosing a certain path of execution. f) If the loop-continuation condition in a for header is initially ___________ , the program does not execute the for statement’s body. g) Methods that perform common tasks and do not require objects are called _____________ methods.

Find and correct the error(s) in each of the following segments of code: a) for ( i = 100, i >= 1, i++ ) System.out.println( i ); b) The following code should print whether integer value is odd or even: switch ( value % 2 ) { case 0: System.out.println( "Even integer" ); case 1: System.out.println( "Odd integer" ); } c) The following code should output the odd integers from 19 to 1: for ( i = 19; i >= 1; i += 2 ) System.out.println( i ); d) The following code should output the even integers from 2 to 100: counter = 2; do { System.out.println( counter ); counter += 2; } While ( counter < 100 );

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