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(Binary Tree Search) Write method binaryTreeSearch, which attempts to locate a specified value in a binary-search-tree object. The method should take as an argument a search key to be located. If the node containing the search key is found, the method should return a reference to that node; otherwise, it should return a null reference.

Short Answer

Expert verified
Use a recursive function to search nodes until finding the key or reaching a null node.

Step by step solution

01

Understand the Binary Search Tree

A binary search tree (BST) is a tree data structure where each node has at most two children, left and right. For each node, all values in the left subtree are smaller, and all values in the right subtree are greater, which facilitates efficient searching.
02

Determine the Base Cases

The binary search tree search can be broken into base cases: if the current node is null (tree is empty or we've reached a leaf), our search has failed and we should return null. If the current node contains the search key, the search is successful and we should return that node.
03

Implement Recursive Search Logic

If the base cases are not met, compare the search key with the current node's key. If the search key is less than the node's key, recursively search the left subtree. If the search key is greater, recursively search the right subtree.
04

Write the BinaryTreeSearch Method

``` Node binaryTreeSearch(Node root, int key) { if (root == null || root.key == key) return root; if (key < root.key) return binaryTreeSearch(root.left, key); return binaryTreeSearch(root.right, key); } ``` This method applies the logic laid out in previous steps: The BST is traversed recursively until the key is found or null is returned.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tree Data Structure
A binary search tree (BST) is a fundamental example of a tree data structure. Think of it like an upside-down tree where each point, called a "node," has branches leading out. In a BST:
  • Each node can have at most two children: a left child and a right child.
  • The left child contains values less than the parent node.
  • The right child contains values greater than the parent node.
This structured arrangement makes the binary search tree an efficient way to store data for quick access, insertion, and deletion.
For instance, if you're looking to find or add a value in the tree, you can effectively ignore half of the tree at each step based on the value you are dealing with. This is a major advantage in terms of time efficiency, as this halves your search space like in a binary search on a sorted array. Compared to other tree structures, BSTs manage to cleverly combine the speed of binary search with the flexibility of dynamic data structures.
Recursive Search
Recursive search is a powerful approach that breaks down a problem into smaller, more manageable chunks, leading towards a solution iteratively.
When it comes to searching within a binary search tree (BST), this approach fits perfectly.
In a recursive search, we define base cases which act as stopping criteria:
  • If the tree is empty (node is null), or if a leaf without the desired value is reached, the search concludes as unsuccessful.
  • If the desired value is found in a node, we return that node, marking the search successful.
Once the base cases are defined, the recursive logic guides the search:
Compare the search key with the current node's value, and decide which subtree to explore next. If the search key is smaller, the left subtree is checked; if larger, the right subtree is explored. These steps are repeated until the base conditions are met.
The beauty of this method is its simplicity and efficiency, as it naturally follows the structure of a BST.
Binary Tree Search Method
The binary tree search method is a systematic way to locate a specific value within a binary search tree (BST). This method is underpinned by both the tree's inherent structure and recursive principles.
The method can be summarized into several key actions:
  • Start from the tree's root node.
  • Continuously compare the search key with the current node's value.
  • Based on the comparison, determine whether to search the left or right subtree.
  • Recursively proceed with this comparison until either the desired value is found or a null reference (indicative of an absent node) is reached.
With each recursive call reducing the search area by half, the binary tree search method efficiently narrows down potential locations, making it a fast solution particularly ideal for large datasets.
When implemented correctly, this method is not only effective but also elegantly simple, leveraging recursion to traverse the tree.

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Most popular questions from this chapter

In Exercises \(7.34-7.35,\) we introduced Simpletron Machine Language \((\mathrm{SML}),\) and you implemented a Simpletron computer simulator to execute programs written in SML. In this section, we build a compiler that converts programs written in a high-level programming language to SML. This section "ties" together the entire programming process. You will write programs in this new high-level language, compile them on the compiler you build and run them on the simulator you built in Exercise \(7.35 .\) You should make every effort to implement your compiler in an object-oriented manner. (\text { The Simple Language })\( Before we begin building the compiler, we discuss a simple, yet powerful high-level language similar to early versions of the popular language BASIC. We call the language Simple. Every Simple statement consists of a line number and a Simple instruction. Line numbers must appear in ascending order. Each instruction begins with one of the following Simple commands: rem, input, 1 et, print, goto, if/goto or end (see Fig. 17.22 ). All commands except end can be used repeatedly. Simple evaluates only integer expressions using the \)+,-, *\( and / operators. These operators have the same precedence as in Java. Parentheses can be used to change the order of evaluation of an expression. Our Simple compiler recognizes only lowercase letters. All characters in a Simple file should be lowercase. (Uppercase letters result in a syntax error unless they appear in a rem statement, in which case they are ignored.) A variable name is a single letter. Simple does not allow descriptive variable names, so variables should be explained in remarks to indicate their use in a program. Simple uses only integer variables. Simple does not have variable declarations - merely mentioning a variable name in a program causes the variable to be declared and initialized to zero. The syntax of Simple does not allow string manipulation (reading a string, writing a string, comparing strings, and so on \)) .$ If a string is encountered in a Simple program (after a command other than rem), the compiler generates a syntax error. The first version of our compiler assumes that Simple programs are entered correctly. Exercise 17.29 asks the reader to modify the compiler to perform syntax error checking.

What are the differencesibetween a stack and a queue?

Write a program that creates a linked list object of 10 characters, then creates a second list object containing a copy of the first list, but in reverse order.

Perhaps a more appropriate title for this chapter would have been Reusable Data Structures. Comment on how each of the following entities or concepts contributes to the reusability of data structures: a) classes b) inheritance c) composition

Stacks are used by compilers to help in the process of evaluating expressions and generating machine-language code. In this and the next exercise, we investigate how compilers evaluate arithmetic expressions consisting only of constants, operators and parentheses. Humans generally write expressions like \(3+4\) and \(7 / 9\) in which the operator \((+\text { or } / \text { here })\) is written between its operands- -this is called infix notation. Computers "prefer" postfix notation, in which the operator is written to the right of its two operands. The preceding infix expressions would appear in postfix notation as \(34+\) and \(79 /\), respectively. To evaluate a complex infix expression, a compiler would first convert the expression to postfix notation and evaluate the postfix version. Each of these algorithms requires only a single left-toright pass of the expression. Each algorithm uses a stack object in support of its operation, but each uses the stack for a different purpose. In this exercise, you will write a Java version of the infix-to-postfix conversion algorithm. In the next exercise, you will write a Java version of the postfix expression evaluation algorithm. In a later exercise, you will discover that code you write in this exercise can help you implement a complete working compiler. Write class InfixToPostfixConverter to convert an ordinary infix arithmetic expression (assume a valid expression is entered) with single-digit integers such as $$(6+2) * 5-8 / 4$$ to a postfix expression. The postfix version of the preceding infix expression is (note that no parentheses are needed $$62+5 * 84 /-$$ The program should read the expression into StringBuffer infix and use one of the stack classes implemented in this chapter to help create the postfix expression in StringBuffer postfix. The algorithm for creating a postfix expression is as follows: a) Push a left parenthesis '(' on the stack. b) Append a right parenthesis ')' to the end of infix. c) While the stack is not empty, read infix from left to right and do the following: If the current character in infix is a digit, append it to postfix. If the current character in infix is a left parenthesis, push it onto the stack. If the current character in infix is an operator: Pop operators (if there are any) at the top of the stack while they have equal or higher precedence than the current operator, and append the popped operators to postfix. Push the current character in infix onto the stack. If the current character in infix is a right parenthesis: Pop operators from the top of the stack and append them to postfix until a left parenthesis is at the top of the stack. Pop (and discard) the left parenthesis from the stack. The following arithmetic operations are allowed in an expression: \+ addition \- subtraction * multiplication / division ^ exponentiation % remainder The stack should be maintained with stack nodes that each contain an instance variable and a reference to the next stack node. Some of the methods you may want to provide are as follows: a) Method convertToPostfix, which converts the infix expression to postfix notation. b) Method isOperator, which determines whether c is an operator. c) Method precedence, which determines whether the precedence of operator1 (from the infix expression) is less than, equal to or greater than the precedence of operator2 (from the stack). The method returns true if operator1 has lower precedence than operator2. Otherwise, false is returned. d) Method stackTop (this should be added to the stack class), which returns the top value of the stack without popping the stack.

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