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(Print an Array Backward) Write a recursive method stringReverse that takes a character array containing a string as an argument and prints the string backward. [Hint: Use String method toCharArray, which takes no arguments, to get a char array containing the characters in the String.]

Short Answer

Expert verified
Use `toCharArray` to convert the string, then recursively print the array from end to start.

Step by step solution

01

Convert String to Character Array

Use the `toCharArray()` method to convert the given string into a character array. This will allow you to manipulate each character individually. For example, if the string is `"hello"`, using `toCharArray()` will return `['h', 'e', 'l', 'l', 'o']`.
02

Define the Recursive Method

Create a method named `stringReverse` that takes a character array and an index as parameters. This method will be responsible for reversing the array.
03

Determine the Base Case

In the recursive method, check if the index is less than 0. If so, it means we have traversed the array backward completely, and we should stop the recursion.
04

Print the Current Character

If the base case is not met, print the character at the current index. This corresponds to printing the string backward since you are decreasing the index from the last element to the first.
05

Recursive Call

Make a recursive call to `stringReverse`, decrementing the index by 1. This will process the next character in reverse order (from the end of the array towards the beginning).
06

Initialize the Recursive Process

Call the `stringReverse` method from your main code, passing the character array and the starting index (which should be the last index of the array, i.e., `length - 1`). For example, if the array has 5 elements, start with index 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Character Arrays
When dealing with strings in programming, sometimes it's necessary to process each character individually. This is where character arrays come in handy. A character array is essentially a collection of characters, representing a string where each character can be accessed separately.

In Java, one of the simplest ways to turn a string into a character array is by using the `toCharArray()` method. This method breaks down a string into an array of characters. For example, if you have the string "hello", `toCharArray()` will convert it into `['h', 'e', 'l', 'l', 'o']`. This allows for easy manipulation, as each character can be individually processed or analyzed.

Character arrays are particularly useful in operations where individual character access is necessary, such as reversing a string or performing character replacement. By using arrays, you can iterate over the characters using loops or recursions, providing flexibility and efficiency.
String Manipulation
String manipulation involves the process of changing, editing, or analyzing string data. It's an essential concept in programming, used across numerous applications and languages.

One of the basic forms of string manipulation is reversing a string, which can be achieved through different methods, including loops, built-in functions, or recursion. In the exercise we're looking at, recursion is used to reverse a string by leveraging a character array. This allows us to access and print each character in reverse order.

By employing recursion, we can solve problems that require iterating through the contents of a string. This is especially useful when dealing with problems that require operations like reversing, checking for palindromes, or custom sorting. The use of character arrays in conjunction with string manipulation techniques makes these processes more intuitive and manageable.
Base Case in Recursion
Recursion is a powerful programming technique where a function calls itself to solve a problem. However, it's crucial to define a stopping point for the recursion to avoid infinite loops. This stopping point is called the base case.

In the context of the exercise, the base case is when the index becomes less than zero. This indicates that the recursive function has processed and printed all characters from the string in reverse. Getting this logic right is essential, as the base case ensures the recursion terminates properly.

Establishing a clear and effective base case is key to successful recursive programming. It prevents run-time errors and ensures that your program performs as expected. By carefully considering the base case, you can shape the control flow of your recursive functions to handle complex tasks succinctly and correctly.

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Most popular questions from this chapter

(Time to Calculate Fibonacci Numbers) Enhance the Fibonacci program of Fig. 15.5 so that it calculates the approximate amount of time required to perform the calculation and the number of calls made to the recursive method. For this purpose, call static System method current- TimeMillis, which takes no arguments and returns the computer’s current time in milliseconds. Call this method twice—once before and once after the call to fibonacci. Save each value and cal- culate the difference in the times to determine how many milliseconds were required to perform the calculation. Then, add a variable to the FibonacciCalculator class, and use this variable to deter- mine the number of calls made to method fibonacci. Display your results.

(Palindromes) A palindrome is a string that is spelled the same way forward and backward. Some examples of palindromes are “radar,” “able was i ere i saw elba” and (if spaces are ignored) “a man a plan a canal panama.” Write a recursive method testPalindrome that returns boolean value true if the string stored in the array is a palindrome and false otherwise. The method should ignore spaces and punctuation in the string.

What does the following program do? 1 // Exercise 15.12 Solution: MysteryClass.java 2 3 public class MysteryClass 4 { 5 public int mystery( int array2[], int size ) 6 { 7 if ( size == 1 ) 8 return array2[ 0 ]; 9 else 10 return array2[ size - 1 ] + mystery( array2, size - 1 ); 11 } // end method mystery 12 } // end class MysteryClass 1 // Exercise 15.12 Solution: MysteryTest.java 2 3 public class MysteryTest 4 { 5 public static void main( String args[] ) 6 { 7 MysteryClass mysteryObject = new MysteryClass(); 8 9 int array[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }; 10 11 int result = mysteryObject.mystery( array, array.length ); 12 13 System.out.printf( "Result is: %d\n", result ); 14 } // end method main 15 } // end class MysteryTest

(Eight Queens) A puzzler for chess buffs is the Eight Queens problem, which asks the following: Is it possible to place eight queens on an empty chessboard so that no queen is “attacking” any other (i.e., no two queens are in the same row, in the same column or along the same diagonal)? For instance, if a queen is placed in the upper-left corner of the board, no other queens could be placed in any of the marked squares shown in Fig. 15.23. Solve the problem recursively. [Hint: Your solution should begin with the first column and look for a location in that column where a queen can be placed—initially, place the queen in the first row. The solution should then recursively search the remaining columns. In the first few columns, there will be several locations where a queen may be placed. Take the first available location. If a column is reached with no possible location for a queen, the program should return to the previous column, and move the queen in that column to a new row. This continuous backing up and trying new alternatives is an example of recursive back-tracking.]

What does the following code do? 1 public int mystery( int a, int b ) 2 { 3 if ( b == 1 ) 4 return a; 5 else 6 return a + mystery( a, b - 1 ); 7 } // end method mystery

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