Chapter 5: Problem 9
Assume that a 1 gigaflop machine is connected to a printer that can print 780 characters per second. In the time it takes to print 1 page ( 65 lines of 60 characters per line), how many floating-point operations can the machine perform?
Short Answer
Expert verified
The machine can perform 5 billion floating-point operations.
Step by step solution
01
Calculate Characters on One Page
To find out how many characters are on one page, multiply the number of lines by the number of characters per line. You have 65 lines and 60 characters per line. \( 65 \times 60 = 3900 \) characters per page.
02
Calculate Printing Time
Given that the printer can print 780 characters per second, compute the time it takes to print 3900 characters (the total number of characters on one page).\( \frac{3900}{780} = 5 \) seconds.
03
Define Gigaflop
Understand that 1 gigaflop (GFLOP) represents 1 billion (or \( 10^9 \)) floating-point operations per second.
04
Calculate Floating-Point Operations
Using the gigaflop definition, calculate how many floating-point operations can occur in the time it takes to print one page, which is 5 seconds. Since the machine performs at a rate of 1 GFLOP:\( 1 \times 10^9 \times 5 = 5 \times 10^9 \) floating-point operations.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gigaflop
Gigaflop is a unit of measurement for computational performance, specifically dealing with floating-point operations. It stands for "billion floating-point operations per second". A floating-point operation is a calculation that involves fractional numbers (numbers with decimal points). These calculations are essential in scientific computations and various applications in engineering and graphics.
- Powerful processing: Gigaflops measure how fast a computer can perform calculations, indicating its raw processing power.
- Scientific importance: Handling tasks like climate modeling or molecular simulations demands high gigaflop counts because these require extensive calculations.
- One gigaflop: Means a computer can handle one billion operations per second.
Computational performance
Computational performance refers to the ability of a computer system to efficiently perform tasks and calculations. It is determined by the speed and efficiency of the system in processing data and executing commands.
- Measure of speed: Evaluated by how quickly a computer can process instructions and compute large datasets.
- Importance in technology: High performance allows for faster data analysis, gaming experiences, and the handling of complex algorithms.
- Influence of hardware: Factors like CPU speed, memory capacity, and the number of cores impact computational performance.
Printer speed
Printer speed indicates how quickly a printer can produce pages or specific volumes of print jobs. It is usually measured in pages per minute (ppm) or characters per second (cps). Understanding printer speed is crucial for environments requiring fast document production.
- Efficiency: A high-speed printer is essential for offices with extensive printing needs, reducing wait times and enhancing productivity.
- Different metrics: Some printers focus on characters per second, significant for dot matrix or impact printers, while others use pages per minute.
- Impact on workflow: Faster printers can support quicker decision-making processes and more streamlined operations in professional settings.
Characters per second
Characters per second (cps) is a measure of how many individual characters (letters, numbers, spaces, etc.) can be printed or displayed by a device, typically a printer, in one second. It is an older metric, more commonly associated with dot matrix printers or similar devices where continuous text streams are produced.
- Multiple uses: Not only applies to printers but also to terminal display speeds in computing.
- Relevance: Important when dealing with legacy technology or environments that still use older hardware.
- Understanding speed: Helps in assessing the overall speed of a printer, especially in scenarios where page count might not apply.