Chapter 3: Problem 1
a. Use Gauss's approach to find the following sum: $$ 2+4+6+\ldots+100 $$ b. Use Gauss's approach to find a formula for the sum of the even numbers from 2 to \(2 n\) : $$ 2+4+6+\ldots+2 n $$ Your formula will be an expression involving \(n\).
Short Answer
Expert verified
a. The sum is 2550. b. The formula is \(n(n + 1)\).
Step by step solution
01
Understand the Sequence
The sequence we have is 2, 4, 6, ..., 100. This is an arithmetic sequence where the first term \(a = 2\) and the common difference \(d = 2\).
02
Find the Number of Terms
To find the number of terms in the sequence, use the formula for the last term of an arithmetic sequence: \(a_n = a + (n-1) \cdot d\). Set \(a_n = 100\), \(a = 2\), \(d = 2\) and solve for \(n\):\[100 = 2 + (n-1) \cdot 2\]\[98 = 2(n-1)\]\[49 = n - 1\]\[n = 50\]Therefore, there are 50 terms.
03
Apply Gauss's Formula for the Sum
Gauss's formula for the sum of an arithmetic series is \(S_n = \frac{n}{2} (a + a_n)\). Substitute \(n = 50\), \(a = 2\), and \(a_n = 100\):\[S_{50} = \frac{50}{2} (2 + 100)\]\[S_{50} = 25 \cdot 102\]\[S_{50} = 2550\]
04
Generalize for Any n
Now, to find the sum for \(2, 4, 6, ..., 2n\), use Gauss's approach.The last term \(a_n = 2n\), and the number of terms \(n = \frac{2n}{2} = n\).The formula for the sum is:\[S = \frac{n}{2} (2 + 2n)\]\[S = \frac{n}{2} \cdot 2 (1 + n)\]\[S = n(n + 1)\]
05
Final Step: Solution Verification
Verify the formula with a specific example. If \(n=50\), the sum should be \(50 \cdot 51 = 2550\), which matches the calculation for part (a).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gauss's Formula
Gauss's Formula is a fascinating and efficient way to sum arithmetic sequences. This method was famously used by Carl Friedrich Gauss, a brilliant mathematician, when he was just a child. He used it to effortlessly find the sum of an arithmetic sequence, which saved time and effort compared to traditional methods.
Gauss's Formula for the sum of the first \( n \) terms of an arithmetic sequence is:
This approach is particularly helpful for large sequences where calculating each term individually would be cumbersome.
Gauss's Formula for the sum of the first \( n \) terms of an arithmetic sequence is:
- \( S_n = \frac{n}{2}(a + a_n) \)
This approach is particularly helpful for large sequences where calculating each term individually would be cumbersome.
Sum of Even Numbers
The sum of even numbers forms a special kind of arithmetic series that is both simple and systematic. When you need to find the sum of even numbers, you're actually summing over an arithmetic sequence where the difference between consecutive terms is constant at 2.
This series can be represented as:
Recognizing these series patterns helps streamline calculations and allows the use of precise formulas that directly leverage arithmetic properties.
This series can be represented as:
- \( 2, 4, 6, \ldots, 2n \)
Recognizing these series patterns helps streamline calculations and allows the use of precise formulas that directly leverage arithmetic properties.
Arithmetic Sequence
An Arithmetic Sequence is a sequence of numbers in which each term after the first is obtained by adding a constant difference, \( d \), to the previous term. It follows this general form:
- \( a, a+d, a+2d, a+3d, \ldots \)
- \( a_n = a + (n-1)d \)
Sequence Formula
Understanding the Sequence Formula is key to solving problems involving sums of sequences. Arithmetic sequences and formulas are straightforward once you know the basic concepts involved. The Sequence Formula, especially in arithmetic series, helps determine characteristics such as the sum, the number of terms, and the nth term.
For the sum of the first \( n \) even numbers, the formula simplifies to:
By understanding this, you can generalize the approach to any sequence of even numbers, making it straightforward to compute large sums without performing repetitive addition. Using this formula, the calculations become more manageable and efficient, underscoring the power of mathematical patterns and formulas in tackling otherwise complex numerical problems.
For the sum of the first \( n \) even numbers, the formula simplifies to:
- \( S = n(n + 1) \)
By understanding this, you can generalize the approach to any sequence of even numbers, making it straightforward to compute large sums without performing repetitive addition. Using this formula, the calculations become more manageable and efficient, underscoring the power of mathematical patterns and formulas in tackling otherwise complex numerical problems.