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Prove that NTIME(n)ΦPSPACE.

Short Answer

Expert verified

NTIME (n) is strict subset of PSPACE (n).

At most t(n) tape cells on each branch can be used by any Turning machine that operates in time t(n) on each computation branch. So, it can be stated that NTIME ΦNSPACE (n).

Step by step solution

01

Considering the Savitch’s theorem

Now, consider the Savitch’s theorem which says that: “Let f:NR

be a function with fnnthen NSPACE(f(n)) SPACE((f(n))2). Therefore according to Savitch’s theorem NTIME (n) PSPACE(n2).

02

Considering the space hierarchy theorem

Now, consider the space hierarchy theorem which says that “if g is space-constructible (1n 1g(n) can be computed in space o(g(n))), f(n)=o(g(n)) then SPACE(f (n)) ΦSPACE(g(n)).

Therefore, according to space hierarchy theorem it can be said that SPACE(n2) ΦSPACE(n3). The result follows because SPACE(n3) PSPACE.

Hence NTIME (n)ΦPSPACE(n).

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