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Let A={M|MisaDFAthatdoesn'tacceptanystringcontianinganoddnumberof1s}. Show that A is decidable.

Short Answer

Expert verified

A is decidable.

Step by step solution

01

Decidable languages

A language is said to be decidable if the inputs of a language are accepted by a Deterministic Finite Automata.

02

Explanation

A language is decidable if the input string of a language is accepted by a Turing Machine. Consider the Turing machine M that decides the language A

The following TM decides A.

“On inputM

  1. Construct a DFA, Dwhich accepts every string containing an odd number of 1s.
  2. Construct a DFA, B such thatLB=LMLD.
  3. Test whether LB=ϕ,using the EDFAdecider T from the Theorem 4.4.
  4. If Taccepts, accept; if T rejects, reject.”

Therefore, the language A=M|MisaDFAthatdoesn'tacceptanystringcontianinganoddnumberof1s is decidable, and has been proven.

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