Chapter 11: Problem 14
Why is the domain-key normal form (DKNF) known as the ultimate normal form?
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 11: Problem 14
Why is the domain-key normal form (DKNF) known as the ultimate normal form?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeDefine join dependencies and fifth normal form. Why is \(5 \mathrm{NF}\) also called project. join normal form (PJNF)?
What is meant by the attribute preservation condition on a decomposition?
Define fourth normal form. When is it violated? Why is it useful?
, YEAR, PRICE, MANUF_PLANT, COLOR), which is abbreviated as REFRIG(M, Y, P, MP, C), and the following set \(F\) of functional dependenci… # Consider the relation REFRIC(MODEL#, YEAR, PRICE, MANUF_PLANT, COLOR), which is abbreviated as REFRIG(M, Y, P, MP, C), and the following set \(F\) of functional dependencies: \(F=\\{M \rightarrow M P,\\{M, Y\\} \rightarrow P, M P \rightarrow C\\}\) a. Evaluate each of the following as a candidate key for REFRIG, giving reasons why it can or cannot be a key: \(\\{\mathrm{M}\\},\\{\mathrm{M}, \mathrm{Y}\\},\\{\mathrm{M}, \mathrm{C}\\}\) b. Based on the above key determination, state whether the relation REFRIG is in \(3 \mathrm{NF}\) and in BCNF, giving proper reasons. c. Consider the decomposition of REFRIG into \(D=\\{\mathrm{R} 1(\mathrm{M}, \mathrm{Y}, \mathrm{P}), \mathrm{R} 2(\mathrm{M}, \mathrm{MP}, \mathrm{C})\\}\) Is this decomposition lossless? Show why. (You may consult the test under Property LJ 1 in Section \(11.1 .4 .\)
Why can we not guarantee that BCNF relation schemas will be produced by dependency-preserving decompositions of non-BCNF relation schemas? Give a counterexample to illustrate this point.
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