Chapter 8: Problem 13
When a roulette wheel is spun once, there are 38 possible outcomes: 18 red, 18 black. and 2 green (if the outcome is green the house wins all bets). If a wheel is spun twice, all \(38 \cdot 38\) outcomes are equally likely. If you are told that in two spins at least one resulted in a green outcome, what is the probability that both outcomes were green?
Short Answer
Step by step solution
Understanding the Problem
Calculate Total Outcomes with at Least One Green
Calculate Outcomes with Both Spins Green
Calculate the Desired Probability
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Roulette Probabilities
In a scenario where the roulette wheel is spun twice, you are looking at a much larger set of possible outcomes—exactly 1444. This is calculated by multiplying the 38 possible outcomes from the first spin by the 38 possible outcomes from the second spin.
For calculating the probability of rolling certain outcomes, it's often interesting to determine the likelihood when specific conditions are met. For instance, if you know that at least one green has appeared in the two spins, you may be curious about the probability of both being green. This involves a concept known as conditional probability and makes the world of roulette probabilities both intriguing and strategic.
Probability Theory
At its core, probability theory assigns a numerical value between 0 and 1 to an event, where 0 indicates impossibility and 1 indicates certainty. For example, the probability of getting a green outcome in one spin of the roulette wheel is \( \frac{2}{38}\). For two independent events, like two spins of a roulette wheel, probability theory often involves multiplication or addition rules depending on whether the events are independent or dependent, mutually exclusive, or overlapping.
Conditional probability, a vital part of probability theory, is particularly useful. It deals with the probability of one event occurring given another event has already occurred. The formula for conditional probability is \[P(A | B) = \frac{P(A \cap B)}{P(B)}\]. This allows us to refine probabilities based on additional information, making predictions and decisions more accurate.
Discrete Mathematics
One key aspect of discrete mathematics in probability is counting the number of elements in a set, which is essential for understanding probabilities. For instance, in the case of the roulette wheel, knowing there are 38 possibilities helps determine the probability of different outcomes.
Another important concept from discrete mathematics is the use of combinatorics to determine the number of possible configurations or outcomes, allowing us to handle complex probability calculations. Without these tools, calculating probabilities in scenarios with multiple possible events happening in sequence, like our spinning roulette wheel, would be daunting. As such, discrete mathematics offers essential techniques for breaking down and solving probability problems, making it indispensable for understanding how games of chance like roulette are analyzed.