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Suppose \(S\) is a set with \(k\) elements. How many elements are in \(S^{n}\), the cross product \(S \times S \times \cdots \times S\) of \(n\) copies of \(S ?\)

Short Answer

Expert verified
The set \( S^n \) has \( k^n \) elements.

Step by step solution

01

Understanding the Cross Product

The cross product \( S^n \) is an operation where we take the set \( S \) and combine it with itself \( n \) times. Each element of \( S^n \) is an ordered \( n \)-tuple where each position in the tuple can be filled by any of the \( k \) elements from \( S \).
02

Counting the Possibilities for One Tuple

For each of the \( n \) positions in the tuple, we can choose any of the \( k \) elements from set \( S \). This means for the first position, there are \( k \) choices, for the second, there are \( k \) choices, and so on.
03

Calculating the Total Number of Tuples in the Cross Product

Since each position is independent of the others, we multiply the number of choices for each position. Therefore, the total number of elements in the cross product set \( S^n \) is given by multiplying \( k \) choices for each of the \( n \) positions. Thus, the number of elements in \( S^n \) is \( k^n \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Set Theory
Set theory is a branch of mathematics that studies the concept of collections, known as sets, and is fundamental to many areas of mathematics. Here are some core ideas that will help you understand this topic better:
  • Definition of a Set: A set is simply a collection of distinct objects, which can be anything like numbers, letters, or even other sets.
  • Elements: These are the objects contained within a set. For example, in a set of numbers like {1, 2, 3}, the elements are 1, 2, and 3.
  • Notation: Sets are usually denoted by capital letters, and elements within a set are listed within curly braces. For example, a set might be written as \(S = \{a, b, c\}\).
  • Operations: Sets can undergo operations such as union, intersection, and Cartesian products to create new sets.
In this exercise, we specifically look at the Cartesian Product. This involves combining sets in a way to form pairs, triplets, or n-tuples that showcase all possible combinations of elements from the involved sets.
Exploring n-Tuples
n-Tuples are an essential concept when dealing with Cartesian Products. To grasp them more deeply:
  • Definition: An n-tuple is an ordered list or sequence of \(n\) elements, where \(n\) represents the number of elements in the sequence. The order of these elements is crucial, as it distinguishes one n-tuple from another.
  • Example: Consider a 2-tuple, known as an ordered pair, like (x, y). The position of each element is crucial, so (x, y) is different from (y, x) unless x = y.
  • In the Context of Sets: When we talk about the Cartesian Product \(S^n\), we're forming n-tuples from a set \(S\) where each position in the n-tuple can be any element from \(S\).
  • Real-World Application: n-Tuples can represent coordinates in space, where a 3-tuple (x, y, z) can represent points in three-dimensional space.
The concept of n-tuples allows for detailed representations and combinations of elements, which is critical in calculus, computer science, and more.
Diving into Combinatorics
Combinatorics is the study of counting, arranging, and combining objects, and it plays a major role in this exercise.
  • Counting Possibilities: When forming the Cartesian Product \(S^n\), combinatorics helps us determine how many ways we can arrange \(k\) elements from set \(S\) in n-tuples.
  • Independent Choices: In this context, each choice for an element in an n-tuple is independent of the others. Thus, multiplying the number of choices for each position gives the total number of combinations.
  • Formula Derivation: The formula \(k^n\) comes from the fact that each of the \(n\) positions in the n-tuple can be filled in \(k\) different ways, independently of each other.
  • Applications in Probability: Combinatorics is vital in calculating probabilities, creating algorithms, and even in cryptographic systems where understanding the number of possible combinations aids security.
This foundational pillar of mathematics provides the tools to manage complex calculations and arrangements, making it invaluable across various scientific and practical domains.

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Most popular questions from this chapter

In a fierce battle, not less than \(70 \%\) of the soldiers lost one eye, not less than \(75 \%\) lost one ear, not less than \(80 \%\) lost one hand, and not less than \(85 \%\) lost one leg. What is the smallest percentage who could have lost simultaneously one car, one eye, one hand, and one leg? This problem comes from Tangled Tales by Lewis Carroll, the author of Alice in Wonderland.

A penny, a nickel, and a dime are shaken together and thrown. Suppose that the nickel turns up heads twice as frequently as the penny and that the dime turns up heads half as frequently as the nickel. Define a sample space, and using the frequency interpretation, assign a reasonable probability density function based on the assumption that the penny is a fair coin.

Suppose that \(\Omega\) is a sample space with a probability density function \(p\), and suppose that \(A \subseteq \Omega\). Let \(P(A)\) denote the probability of \(A\). Assume that \(P(A)>0 .\) Define a function \(p_{1}\) on \(A\) as follows: For \(\omega \in A, p_{1}(\omega)=p(\omega) / P(A)\). (a) Show that if \(\omega_{1}, \omega_{2} \in A\) and \(p\left(\omega_{1}\right), p\left(\omega_{2}\right) \neq 0,\) then \(\frac{p\left(\omega_{1}\right)}{p\left(\omega_{2}\right)}=\frac{p_{1}\left(\omega_{1}\right)}{p_{1}\left(\omega_{2}\right)}\) (b) Show that if \(B\) and \(C\) are nonempty subsets of \(A\) with elements that have positive probabilities, then \(\frac{P(B)}{P(C)}=\frac{P_{1}(B)}{P_{1}(C)}\) (c) Show that \(p_{1}\) is a probability density function on \(\Omega_{1}=A\).

Consider a game based on the days of a 31 -day month. A day is chosen at randomsay, by spinning a spinner. The prize is a number of dollars equal to the sum of the digits in the date of the chosen day, For example, choosing the 31 st of the month pays \(\$ 3+\$ 1=\$ 4,\) as does choosing the fourth day of the month. (a) Set up the underlying sample space \(\Omega\) and its probability density, the value of which at \(\omega\) gives the reward associated with \(\omega\). (b) Define a random variable \(X(\omega)\) on \(\Omega\) with a value at \(\omega\) that gives the reward associated with \(\omega\). (c) Set up a sample space \(\Omega_{X}\) consisting of the elements in the range of \(X,\) and give the probability distribution \(p x\) on \(\Omega_{X}\) arising from \(X\). (d) Determine \(P(X=6)\). (e) Determine \(P(2 \leq X \leq 4)=P(\omega: 2 \leq X(\omega) \leq 4)\). (f) Determine \(P(X>10)=P(\omega: X(\omega)>10)\).

What is the probability that a card drawn at random from a 52 -card deck will be a heart or an even-numbered card?

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