Chapter 5: Problem 18
Prove that \(n^{3} \in \mathrm{O}\left(n^{\pi}\right)\) and that \(n^{\pi} \notin \mathrm{O}\left(n^{3}\right)\).
Short Answer
Expert verified
\(n^3 \in \mathrm{O}(n^\pi)\), but \(n^\pi \notin \mathrm{O}(n^3)\).
Step by step solution
01
Understand the Definitions
First, recall that the big O notation, \( f(n) \in \mathrm{O}(g(n)) \), means that there exists a constant \( C > 0 \) and \( n_0 \) such that for all \( n \geq n_0 \), \( |f(n)| \leq C|g(n)| \). Our goal is to show this relation holds for \( n^3 \) and \( n^{\pi} \) in both directions specified.
02
Prove that \( n^3 \in O(n^{\pi}) \)
Consider the function \( f(n) = n^3 \) and \( g(n) = n^{\pi} \). We want to find constants \( C \) and \( n_0 \) such that \( n^3 \leq C n^{\pi} \) for all \( n \geq n_0 \). Since \( \pi \approx 3.14 \), it follows naturally that \( n^3 \leq n^{3.14} \) for sufficiently large \( n \). For example, let \( C = 1 \) and \( n_0 = 1 \), so for \( n \geq n_0 \), \( n^3 \leq n^{3.14} = C \cdot n^{\pi} \). This shows \( n^3 \in \mathrm{O}(n^{\pi}) \).
03
Counterexample to Show \( n^{\pi} \notin O(n^3) \)
Now let's consider the reverse, where \( f(n) = n^{\pi} \) and \( g(n) = n^3 \). Suppose \( n^{\pi} \in \mathrm{O}(n^3) \), then there must exist constants \( C' > 0 \) and \( n_0' \) such that \( n^{3.14} \leq C' n^3 \) for all \( n \geq n_0' \). However, as \( n \) grows larger, the factor \( n^{0.14} \) grows unbounded since \( 0.14 > 0 \), and thus, \( n^{3.14} \) will exceed \( C' n^3 \) for any constant \( C' \). This contradiction means \( n^{\pi} otin \mathrm{O}(n^3) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Asymptotic Analysis
In algorithm analysis, asymptotic analysis is a crucial method to evaluate the efficiency of algorithms. It allows us to describe the limiting behavior of a function when the argument tends towards a specific point or infinity. This helps in understanding how algorithms perform as the input size becomes large.
Asymptotic analysis focuses on the growth rates of functions, which can be expressed using Big O notation. Big O helps us approximate the upper bound of a function. It does not account for constant factors and lower order terms, which become negligible as the input size grows.
Asymptotic analysis focuses on the growth rates of functions, which can be expressed using Big O notation. Big O helps us approximate the upper bound of a function. It does not account for constant factors and lower order terms, which become negligible as the input size grows.
- It provides a way to classify algorithms by how they respond to changes in the input size. For example, O(n), O(log n), and O(n²) signify different growth rates and behavior.
- This type of analysis is most useful in comparing algorithms and predicting their performance in various contexts.
Function Growth
Function growth in mathematics and computer science describes how the output of a function increases as the input increases. It is vital for understanding algorithm efficiency and performance, particularly with large data sets.
In our exercise, comparing the functions \(n^3\) and \(n^{\pi}\) illustrates function growth. Since \(\pi \approx 3.14\), we can see that \(n^{\pi}\) grows slightly faster than \(n^3\).
In our exercise, comparing the functions \(n^3\) and \(n^{\pi}\) illustrates function growth. Since \(\pi \approx 3.14\), we can see that \(n^{\pi}\) grows slightly faster than \(n^3\).
- The concept of growth rate is relative and depends on the context of comparison. In the form of Big O notation, growth rates help us to categorize the efficiency of different algorithms.
- Exponential functions, such as \(2^n\), grow faster than polynomial functions like \(n^3\), which are the focus of many algorithmic studies.
Mathematical Proofs
Mathematical proofs are logical arguments that establish the truth of mathematical statements. In computer science, proofs often show why certain properties hold for algorithms or functions. Proofs can use direct arguments, counterexamples, or induction among other methods.
For our exercise, we first proved that \(n^3 \in \mathrm{O}(n^{\pi})\) by showing that \(n^3\) is less than or equal to \(n^{3.14}\) for sufficiently large values of \(n\). This is a straightforward application of the definition of Big O notation.
For our exercise, we first proved that \(n^3 \in \mathrm{O}(n^{\pi})\) by showing that \(n^3\) is less than or equal to \(n^{3.14}\) for sufficiently large values of \(n\). This is a straightforward application of the definition of Big O notation.
- A direct approach was used by assigning specific values to constants \(C\) and \(n_0\), demonstrating that the inequality holds from a certain point onward.
- To disprove \(n^{\pi} otin \mathrm{O}(n^3)\), a counterexample was used. This method highlighted that \(n^{3.14}\) grows unbounded in comparison to \(n^3\) as \(n\) increases.