Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Select 100 integers from the integers \(1,2, \ldots, 200\) such that no one of the chosen values is divisible by any other chosen value. Show that if one of the 100 integers chosen from \(1,2, \ldots, 200\) is less than \(16,\) then one of those 100 numbers is divisible by another.

Short Answer

Expert verified
Choosing an integer less than 16 creates unavoidable divisibility conflicts.

Step by step solution

01

Understand the Problem

We need to select 100 integers from the range of 1 to 200 such that no chosen integer divides another. Additionally, we need to show that selecting an integer less than 16 violates this condition.
02

Identify Potential Divisors

Within any group of integers that includes a range from 1 to a larger integer, smaller numbers are often divisors of the larger numbers. Therefore, any integer less than 16 will have a higher potential to divide another because many multiples of numbers less than 16 exist within 1 to 200.
03

Consider Multiples of Small Numbers

Any integer less than 16 will have several multiples within the range. For instance, 2 has multiples like 4, 8, 16, ..., and 15 has 30, 45, 60, and so on up to 200. These multiples cannot all be selected due to divisibility constraints.
04

Attempt Maximum Non-Divisibility Selection

Try selecting integers greater than or equal to 16, considering each subsequent number carefully to prevent divisibility conflicts. If we choose solely from numbers like 101 to 200, we avoid most divisibility since these are not multiples of numbers less than 16.
05

Prove the Divisibility Conflict

If any number less than 16 is chosen, it has numerous multiples up to 200, automatically reducing available choices that are not divisible by smaller selected numbers. This leads to a scenario where 100 non-divisible integers cannot be selected while including numbers less than 16.
06

Conclusion

Thus, choosing an integer less than 16 leads to inevitable divisibility within the selected 100 integers, confirming the problem statement.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integer Selection
In discrete mathematics, integer selection involves picking certain numbers from a given set of numbers under specific conditions. In our exercise, we were tasked with selecting 100 integers from the numbers ranging from 1 to 200. However, there was a key condition: no chosen integer should be divisible by another. This constraint limits the possibilities for selection significantly, as it requires careful analysis to ensure that our selected set respects these rules. When attempting to choose such a set of integers, it's crucial to consider relationships between numbers, especially focusing on divisibility, which directly impacts how many numbers can fit within your criteria. Integer selection problems like these frequently appear in mathematical competitions and tests, showcasing the depth of problem-solving skills and understanding required, making them excellent practice for enhancing logical reasoning.
Divisibility Rules
Divisibility rules help determine if one integer is divisible by another. These rules are fundamental in tackling problems where divisibility is a primary condition. In the context of our problem, selecting integers while avoiding divisibility among them, it's essential to recognize that an integer is divisible by another if there exists a whole number that can multiply with the smaller integer to result in the larger one. For instance, 4 divides 16 because 4 multiplied by 4 equals 16. Numbers less than 16 were highlighted as problematic due to their capability to have multiple occurrences in any list within 1 to 200. Therefore, avoiding numbers below 16 is an effective strategy to prevent any two numbers in our selected set from dividing each other. By applying divisibility rules, one can carefully construct a set of integers that strictly adheres to the non-divisibility rule required in the exercise.
Set Theory
Set theory serves a pivotal role in understanding how collections of numbers (or objects) interact and are formulated under various conditions. In this exercise, the set of integers from 1 to 200 can be considered as our universal set. From this, we are tasked with creating a subset of 100 integers that do not divide each other. The interplay between subsets and the universal set is where the challenge lies. Each choice affects the subsequent potential choices, requiring a strategic approach. By leveraging set theory, one can visualize the relationships more clearly, using concepts like intersection (common elements of sets), union (combining of different sets), and complements (elements not in a set) to comprehend the limitations and possibilities in forming such subsets. Understanding set theory fundamentals allows students to better tackle complex discrete math problems, enabling them to develop well-reasoned strategies for integer selection while meeting given conditions.
Combinatorial Problems
Combinatorial problems often involve finding an optimal arrangement or selection from a discrete set of items, subject to certain restrictions. In our integer selection challenge, we approached a combinatorial problem with the restriction that none of the integers selected can divide another. Combinatorial considerations must be made, factoring in the number of possible selections. How do we ensure the largest selection under the condition that no two numbers are divisible? One solution was to focus on integers from 16 and upwards. This decision was influenced by eliminating potential divisibility by excluding numbers below 16. Such an approach highlights not just the importance of considering single constraints, but also how intersecting constraints can heavily impact outcomes. Practicing combinatorial problems sharpens one's ability to analyze multiple conditions and deduce possible solutions effectively.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A man has 10 black socks and 11 blue socks scrambled in a drawer. Still half- asleep. the man reaches in the drawer to get a pair of matching socks. How many socks should he select, one at a time, before he will be sure that he has a matching pair. How many selections are needed to be sure he has a blue pair?

Let \(A\) and \(B\) be nonempty sets, and let \(F: A \rightarrow B\) be a function. Prove that the following are equivalent: (a) \(F\) is \(I-I\). (b) There is a function \(G: B \rightarrow A\) such that \(G \circ F=I d_{A}\). (c) For any set \(C\) and for functions \(H_{1}: C \rightarrow A\) and \(H_{2}: C \rightarrow A,\) if \(F \circ H_{1}=F \circ\) \(\mathrm{H}_{2},\) then \(\mathrm{H}_{\mathrm{l}}=\mathrm{H}_{2}\)

If looked at appropriately, the definition of a function as a set of ordered pairs and the intuitive notion that a function is something given by a rule are equivalent. Develop that equivalence here. Assume that \(F\) has a finite domain \(\\{0,1,2, \ldots, n-1\\}\) and a finite codomain \(\\{0,1,2, \ldots, m-1]\). (a) Suppose \(F\) is a function given as a set of ordered pairs. For an input \(x_{1}\), give a rule for calculating \(F\left(x_{1}\right)\). Use \(F\) (or its graph) in your rule. (b) Suppose the function \(F\) is given by a rule. Express \(F\) as a set of ordered pairs.

(a) Show that the set of all finite sequences of elements of the one-element set \\{0\\} is countably infinite. (b) Show that the set of all finite sequences of elements of the two-element set (0,1] is countably infinite. (c) Challenge: Show that the set of all finite sequences of natural numbers is countably infinite. (Hint: Use a diagonal argument.)

Let \(X=\\{a, b\\}\) (a) There are nine partial functions \(F: X \rightarrow X\). List them. (b) There are four functions \(F: X \rightarrow X\). List them. (c) List all \(l-l\) functions \(F: X \rightarrow X\). (d) List all onto functions \(F: X \rightarrow X\).

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free