Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Let \(X=\\{1,2,3,4 \mid\) and \(Y=\\{5,6,7,8,9\\}\). Let \(F=I(1,5),(2,7),(4,9),(3,8)\\}\) Show that \(F\) is a function from \(X\) to \(Y\). Find \(F^{-1}\), and list its elements. Is \(F^{-1}\) a function? Why, or why not?

Short Answer

Expert verified
F is a function. F^{-1} = \{(5, 1), (7, 2), (9, 4), (8, 3)\}, which is also a function.

Step by step solution

01

Understand the definition of a function

A relation from set \(X\) to set \(Y\) is a function if every element in set \(X\) is associated with exactly one element in set \(Y\). In this case, set \(F\) has four pairs: \((1,5), (2,7), (4,9), (3,8)\). We will check if every element from \(X = \{1, 2, 3, 4\}\) is represented exactly once in these pairs.
02

Verify each element in domain X

Check each pair in \(F\) to confirm that each element in \(X\) appears exactly once as the first component of a pair. \((1, 5)\) has 1 from \(X\), \((2, 7)\) has 2 from \(X\), \((4, 9)\) has 4 from \(X\), and \((3, 8)\) has 3 from \(X\). Since all elements of \(X\) appear exactly once, \(F\) is indeed a function from \(X\) to \(Y\).
03

Find the inverse of F

To find \(F^{-1}\), switch the elements in each pair so that if \((a, b)\) is in \(F\), \((b, a)\) will be in \(F^{-1}\). Thus, \(F^{-1} = \{(5, 1), (7, 2), (9, 4), (8, 3)\}\).
04

Determine if the inverse F^{-1} is a function

A relation is a function if every element in the domain is associated with exactly one element in the codomain. In \(F^{-1}\), the elements 5, 7, 9, and 8 appear exactly once as the first element of each pair. Since \(F^{-1}\) satisfies the criteria of a function, it is a function.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Functions in Discrete Mathematics
Functions are fundamental concepts in discrete mathematics. They create a relationship between two sets, mapping each element of the first set (called the domain) to one and only one element of the second set (called the codomain). Think of functions as special kinds of relations that bring order by ensuring each input has a specific output.
- A function from set \(X\) to set \(Y\) requires that every element in \(X\) is associated with exactly one element in \(Y\).
- This uniqueness requirement means that no element in \(X\) can map to more than one element in \(Y\).
In the given exercise, the set \(F\) consists of pairs \((1, 5), (2, 7), (4, 9), (3, 8)\).
As each element from \(X = \{1, 2, 3, 4\}\) appears exactly once as the first component of a pair, \(F\) is indeed a function.
Functions help in organizing data and creating predictable outcomes, which is crucial in computational sciences.
Understanding Inverse Functions
An inverse function essentially reverses the roles of the domain and codomain. If \((a, b)\) is in a function \(F\), the inverse function \(F^{-1}\) will contain \((b, a)\). This flipping ensures that we can trace back from the output to the input. The inverse function provides a kind of mirror image of the original function.
- To find an inverse, swap each pair's components in the function.
- An important aspect is that not all functions have an inverse. For \(F^{-1}\) to be a function, every element in the new domain must correspond to exactly one element in the new codomain.
In our exercise, by swapping the elements of \(F\), we get \(F^{-1} = \{(5, 1), (7, 2), (9, 4), (8, 3)\}\).
The set \(F^{-1}\) meets the requirements of a function because each element 5, 7, 9, and 8 is the first element exactly once.
Understanding inverse functions is essential for exploring reversible processes and solving equations backward.
Exploring Sets in Mathematics
Sets are collections of distinct objects or elements. They form the foundation of discrete mathematics and are used to define relations and functions. In sets, order does not matter, and each element is unique.
- Sets are usually denoted by curly braces, e.g., \(X = \{1, 2, 3, 4\}\).
- A set can be finite or infinite, but each element can appear only once.
In our exercise, the sets \(X\) and \(Y\) represent the domain and codomain, respectively.
Understanding the characteristics of these sets is crucial when analyzing functions and their inverses.
Set operations such as union, intersection, and difference help us manipulate and understand various mathematical structures.
Relations and Their Types
Relations generalize the idea of functions by associating elements from one set with elements from another set. While a function is a type of relation with a strict rule that each input is paired with a single output, relations do not necessarily have this restriction.
- A relation from set \(X\) to set \(Y\) is a subset of the Cartesian product \(X \times Y\).
- A relation can map multiple elements of its domain to the same element in its codomain.
- However, unlike functions, relations allow an element of the domain to be related to multiple elements in the codomain.
In our problem, \(F\) is both a relation and a function, while \(F^{-1}\) remains a function under the criteria given.
Understanding relations is important for recognizing patterns and structures in data, which can then be constrained to functions for more specific applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free