Chapter 2: Problem 14
Let \(\phi=(p \rightarrow q) \rightarrow((r \wedge \neg s) \rightarrow q)\). For each of the following interpretations of \(p, q, r,\) and \(s,\) compute \(I(\phi)\) using the truth tables for \(\neg, v, \wedge, \rightarrow,\) and \(\leftrightarrow\) (a) \(I(p)=T, I(q)=T, I(r)=F,\) and \(I(s)=T\) (b) \(I(p)=T, I(q)=F, I(r)=T,\) and \(I(s)=F\) (c) \(I(p)=F, I(q)=T, I(r)=T,\) and \(I(s)=F\) (d) \(I(p)=F, I(q)=F, I(r)=T,\) and \(I(s)=F\)
Short Answer
Step by step solution
Define the expression and truth table operations
Evaluate Interpretation (a)
Evaluate Interpretation (b)
Evaluate Interpretation (c)
Evaluate Interpretation (d)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Logical Operations
- Not (\(eg\) ): This unary operation negates the truth value of a proposition. If a statement is true, applying 'not' makes it false, and vice versa.
- And (\(\wedge\)): This binary operation results in true only if both operands are true. Otherwise, it returns false.
- Or (\(\vee\)): Unlike 'and', this operation is true if at least one of the operands is true. It is false only if both are false.
- Implies (\(\rightarrow\)): This somewhat tricky operation is often counterintuitive. It is false only when a true statement implies a false one. In all other cases, it is true.
- Biconditional (\(\leftrightarrow\)): This is true if both operands have the same truth value, either both true or both false.
Propositional Calculus
- individual propositions (like p, q, r)
- logical connectives (like \(\wedge, \vee, eg, \rightarrow,\)and \(\leftrightarrow\))
Truth Value Evaluation
- Begin with the innermost expressions, like \(eg s\),building out to the whole.
- Evaluate each logical operation in the context of its given truth assignments, applying rules such as "\(T \rightarrow F\)is false".
- By constructing a complete truth table, you document each stage of the evaluation, ensuring accuracy in complex logical assessments.