Chapter 2: Problem 11
Write pseudocode for a program that, given a formula \(\phi,\) finds (i) a logically equivalent formula \(\phi^{\prime}\) in CNF and (ii) a logically equivalent formula \(\phi^{\prime \prime}\) in DNF. The algorithm should be recursive (similar to an induction on formulas) and should not involve the construction of truth tables. Prove the algorithm works. This gives an alternate proof of the theorem that every formula is equivalent to a formula in CNF.
Short Answer
Step by step solution
Base Case for Atoms
Recursive Case for Negation
Recursive Case for Disjunction
Recursive Case for Conjunction
Algorithm Proof
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Logical Equivalence
Understanding logical equivalence is crucial when transforming formulas into CNF (Conjunctive Normal Form) or DNF (Disjunctive Normal Form), as we aim to create an equivalent formula that is easier to manipulate or analyze.
To identify logical equivalence, you do not need to construct truth tables. Instead, understanding and applying transformation rules like De Morgan’s laws or the distributive laws can achieve this equivalence transformation.
For instance, if you have two statements, say \(A o B\) and \(eg A \lor B\), they are logically equivalent and prove it without a truth table. Logical equivalence allows these transformations to be seamlessly integrated into algorithms for CNF and DNF conversion.
De Morgan's Laws
- \(eg(A \land B)\) is equivalent to \(eg A \lor eg B\)
- \(eg(A \lor B)\) is equivalent to \(eg A \land eg B\)
By applying these laws, you can ensure that negations are pushed down to the atomic level, which simplifies further transformation processes.
Within the pseudocode for converting formulas to CNF or DNF, whenever a negation operator is encountered, De Morgan's laws guide the manner in which the formula will be broken down and restructured, maintaining logical equivalence.
Distributive Laws
- Conjunction distributes over disjunction: \((A \land (B \lor C))\) is equivalent to \((A \land B) \lor (A \land C)\)
- Disjunction distributes over conjunction: \((A \lor (B \land C))\) is equivalent to \((A \lor B) \land (A \lor C)\)
Conversely, for DNF, disjunctions distribute over conjunctions, presenting the formula as a disjunction of conjunctions.
Applying these laws within the pseudocode transforms the logical structure while retaining its truthfulness and sets the stage for further logical manipulation.
Structural Induction
In the context of CNF and DNF conversion, structural induction validates that every step of the transformation maintains logical equivalence.
The process begins with the simplest base case—atomic formulas—which are inherently in CNF and DNF.
- Base Case: Atomic formulas like \(p\) are in both CNF and DNF.
- Induction Step: Assuming formulas \(\phi_1\) and \(\phi_2\) can be converted to CNF and DNF, show that combined formulas \(eg\phi_1\), \(\phi_1 \land \phi_2\), and \(\phi_1 \lor \phi_2\) can also be converted.