Chapter 1: Problem 21
Prove by induction: The sum of the cubes of any three consecutive natural
numbers is divisible by
Short Answer
Expert verified
The sum of the cubes of any three consecutive natural numbers is divisible by 9.
Step by step solution
01
Base Case
To prove by induction, we first verify the base case. Let's check whether the sum of the cubes of the first three consecutive natural numbers, 1, 2, and 3, is divisible by 9.Calculate: Since 36 is divisible by 9, the base case holds true.
02
Inductive Hypothesis
Assume that for some natural number , the sum of the cubes of three consecutive numbers and is divisible by 9. That means: Where is an integer.
03
Inductive Step
Prove that the sum of the cubes of the next three consecutive numbers, and , is also divisible by 9.Calculate the sum: Using the binomial theorem, expand: Simplifying: Combine like terms: Factor out 9: This shows the expression is divisible by 9.
04
Conclusion
Since both the base case holds and the inductive step is complete, by mathematical induction, the sum of the cubes of any three consecutive natural numbers is divisible by 9.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Natural Numbers
Natural numbers are the numbers that we use for counting. They start from 1 and go on indefinitely: 1, 2, 3, 4, etc. Unlike whole numbers, they do not include zero. Natural numbers are intuitive as they represent real-world quantities like objects or things that we count. Natural numbers can be added, subtracted, multiplied, and divided (except by 0) to produce other natural numbers.
These numbers have properties such as:
- Closure under addition and multiplication: Adding or multiplying two natural numbers will always give another natural number.
- Associative property: The way in which numbers are grouped in an operation does not change the result (e.g., (1 + 2) + 3 is the same as 1 + (2 + 3)).
- Distributive property: The sum of two numbers, each multiplied by a third number, is equal to the sum of each multiplied individually by the third number (e.g., 2*(3 + 4) is the same as 2*3 + 2*4).
Binomial Theorem
The binomial theorem is a powerful tool in algebra that allows us to expand expressions raised to a power, particularly those involving two terms (hence bi-nomial). Given ":[(a+b)^n]", we can expand it to a sum of terms using binomial coefficients. The general form of the binomial expansion is: Each term in the expansion has a coefficient , where is a binomial coefficient and is calculated as . The binomial theorem is particularly useful in proving algebraic identities and solving combinatorial problems. When dealing with cubes of numbers, such as those in our problem, the binomial theorem helps us expand expressions into simpler terms that can be added or factored easily.
Factor
A factor is a number that divides another number completely without leaving any remainder. For instance, 3 is a factor of 9 because 9 divided by 3 equals 3, leaving no remainder. Factors can be found for all integers and are fundamental in simplifying expressions and solving equations.
To find factors, one can divide the number in question by various integers to see if the result is a whole number.
- 1 and the number itself are always factors of any number.
- Numbers can have multiple factors and knowing them is crucial for division and multiplication problems.
Divisibility Rules
Divisibility rules are shortcuts or quick checks to determine if one number divides another completely. These rules ease the process of determining divisibility without performing the actual division. Here are some common divisibility rules:
- A number is divisible by 2 if its last digit is even.
- A number is divisible by 3 if the sum of its digits is divisible by 3.
- A number is divisible by 9 if the sum of its digits is divisible by 9.