Chapter 7: Problem 23
Let \(T\) be a (possibly improper) binary tree with \(n\) nodes, and let \(D\) be the sum of the depths of all the external nodes of \(T .\) Show that if \(T\) has the minimum number of external nodes possible, then \(D\) is \(O(n)\) and if \(T\) has the maximum number of external nodes possible, then \(D\) is \(O(n \log n)\).
Short Answer
Step by step solution
- Recall Definitions
- Minimum Number of External Nodes
- Sum of Depths in a Balanced Tree
- Maximum Number of External Nodes
- Sum of Depths in a Skewed Tree
- Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
binary tree
depth of nodes
external nodes
balanced binary tree
- Search operations: O(log n) time complexity
- Insertions and deletions: Ensure the tree remains balanced
skewed binary tree
- Left Skewed Tree: All nodes have only a left child
- Right Skewed Tree: All nodes have only a right child
algorithm complexity
- Tree Structure: Balanced or skewed trees influence the complexity.
- Operations: Search, insertion, and deletion operations have varying complexities based on tree balance.
- Node Depth: Deeper nodes can increase processing time for certain operations.