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Translate 0×abcdef12into decimal

Short Answer

Expert verified

The translation is:

2882400018

Step by step solution

01

Define Hexadecimal

Hexadecimal is the base 16 number system that represents the 4-bit binary numbers in a simplified way. In hexadecimal the values from 10-15 is represented by the alphabets A-F.

In machine programs, most values will be considered in a hexadecimal format which makes the execution faster.

02

Determine the decimal value

For the given value, the decimal value can be calculated by multiplying each term by the powers of 16 and summing all values.

The calculation is as follows:

0×abcdef12=2×160+1×161+15×162+14×163+13×164+12×165+11×166+10×167

The decimal value of 0×abcdef12is 2882400018

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Most popular questions from this chapter

Question: Write a program in MIPS assembly language to convert an ASCII number string containing positive and negative integer decimal strings, to an integer. Your program should expect register \(a0 to hold the address of a null-terminated string containing some combination of the digits 0 through 9. Your program should compute the integer value equivalent to this string of digits, then place the number in register \)v0. If a non-digit character appears anywhere in the string, your program should stop with the value -1 in register \(v0. For example, if register \)a0 points to a sequence of three bytes 50ten, 52ten, 0ten (the null-terminating string “24”), then when the program stops, register $v0 should contain the value 24ten .

Provide the type and assembly language instruction for the following binary value: 0000 0010 0001 0000 1000 0000 0010 0000two.

[5] Assume for a given processor the CPI of arithmetic instructions is 1, the CPI of load/store instructions is 10, and the CPI of branch instructions is 3.

Assume a program has the following instruction breakdowns: 500 million arithmetic instructions, 300 million load/store instructions, 100 million branch instructions.

2.46.1 [5] <§2.19> Suppose that new, more powerful arithmetic instructions are added to the instruction set. On average, through the use of these more powerful arithmetic instructions, we can reduce the number of arithmetic instructions needed to execute a program by 25%, and the cost of increasing the clock cycle time by only 10%. Is this a good design choice? Why?

2.46.2 [5] <§2.19> Suppose that we find a way to double the performance of arithmetic instructions. What is the overall speedup of our machine? What if we find a way to improve the performance of arithmetic instructions by 10 times?

Question 2.4 [5] For the MIPS assembly instructions below, what is the corresponding C statement? Assume that the variables f, g, h, i, and j are assigned to registers \(s0, \)s1, \(s2, \)s3, and \(s4, respectively. Assume that the base address of the arrays A and B are in registers \)s6 and \(s7, respectively.

sll \)t0, \(s0, 2 # \)t0 = f * 4

add \(t0, \)s6, \(t0 # \)t0 = &A[f]

sll \(t1, \)s1, 2 # \(t1 = g * 4

add \)t1, \(s7, \)t1 # \(t1 = &B[g]

lw \)s0, 0(\(t0) # f = A[f]

addi \)t2, \(t0, 4

lw \)t0, 0(\(t2)

add \)t0, \(t0, \)s0

sw \(t0, 0(\)t1)

Question: If the current value of the PC is 0x1FFFf000, can you use a single jump instruction to get to the PC address as shown in Exercise 2.39?

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