Question

Translate the following loop into C. Assume that the C-level integer i is held in register \(t1, \)s2 holds the C-level integer called result, and \(s0 holds the base address of the integer MemArray.

addi \)t1, \(0, \)0

LOOP: lw \(s1, 0(\)s0)

add \(s2, \)s2, \(s1

addi \)s0, \(s0, 4

addi \)t1, \(t1, 1

slti \)t2, \(t1, 100

bne \)t2, $s0, LOOP

Short answer

The C code:

$$\begin{gathered} for(i=0;i<100;i++)\{ \\ result=MemArray[i]; \\ \} \end{gathered}$$

Step-by-step solution

Definition of loop

Loop is a programming structure used when some statements will be repeatedly executed until the condition is satisfied.

As per the question, these are the following highlights

This Program adds the element in the integer array $s0 of 100 elements.

The base address of the integer MemArray is held by $s0.

Then the integer array in C program will be MemArray

Hence, the C Code is;

$$\begin{gathered} for(i=0;i<100;i++)\{ \\ result=MemArray[i]; \\ \} \end{gathered}$$