Question

For the following C statement, write a minimal sequence of MIPS assembly instructions that does the identical operation. Assume \(t1=A, \)t2=B and $s1 is the base address of C.

$A=C\left[0\right]\square 4;$

Short answer

The sequence of MIPS assembly instructions for the $A=C\left[0\right]\square 4$; is as follows:

lw $t3,0($s1)

sll $t1,$t3,4

Step-by-step solution

Define MIPS logical instructions and Arrays.

The sll and srl are the shift instructions that make the left and a right shift in the bits of the registers. The array can be declared in MIPS through lw and sll instructions. Each Array has the size and the index for each element stored. Array indexing starts from 0 and the elements can be accessed through the index.

Determine the MIPS instruction

Given that, $t1=A and $t2=B. The base address of C is $s1.

To assign the base address of C to $s1, then the lw instruction will be used to load. This will load the element at a 0-byte offset from $s1.

Then for shifting sll instruction is used.

The sequence of MIPS assembly instructions for the $A=C\left[0\right]\square 4$is as follows:

lw $t3,0($s1)

sll $t1,$t3,4