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Provide the type and assembly language instruction for the following binary value: 0000 0010 0001 0000 1000 0000 0010 0000two.

Short Answer

Expert verified

R-type, add $s0, $s0, $s0

Step by step solution

01

Define Instruction Format

The register names of the MIPS assembly languages are mapped to numbers. The registers from $s0 to $s7 are mapped to registers16 to 23, registers $t0 to $t7 mapped to registers 8 to 15.

The instructions are segmented into fields. The first and last will denote the operation of the instruction. The rest of the fields provide information about the operands and the result of the instruction.

02

Determine the type and the assembly language instruction.

There are two types of instructions R-Type and I-Type. R-type refers to the register instructions that have all the fields in the same length and I-type refers to the immediate and the data transfer instructions.

Here, the given binary value has the same length of the value in all the fields.

0000 0010 0001 0000 1000 0000 0010 0000two.

So, the type of instruction is R-type.

Now change the bit format as follows:

6 bits

5 bits

5 bits

5bits

5 bits

6 bits

000000

10000

10000

10000

00000

100000

Convert the hexadecimal values to decimal

6 bits

5 bits

5 bits

5bits

5 bits

6 bits

000000

10000

10000

10000

00000

100000

0

16

16

16

0

16

From the first and the last field, it is clear that this is the add instruction.

16 is the number of the $s0 register.

So the instruction is add $s0, $s0, $s0

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Most popular questions from this chapter

Question: Write a program in MIPS assembly language to convert an ASCII number string containing positive and negative integer decimal strings, to an integer. Your program should expect register \(a0 to hold the address of a null-terminated string containing some combination of the digits 0 through 9. Your program should compute the integer value equivalent to this string of digits, then place the number in register \)v0. If a non-digit character appears anywhere in the string, your program should stop with the value -1 in register \(v0. For example, if register \)a0 points to a sequence of three bytes 50ten, 52ten, 0ten (the null-terminating string “24”), then when the program stops, register $v0 should contain the value 24ten .

Question: Translate the following loop into C. Assume that the C-level integer i is held in register \(t1, \)s2 holds the C-level integer called result, and \(s0 holds the base address of the integer MemArray.

addi \)t1, \(0, \)0

LOOP: lw \(s1, 0(\)s0)

add \(s2, \)s2, \(s1

addi \)s0, \(s0, 4

addi \)t1, \(t1, 1

slti \)t2, \(t1, 100

bne \)t2, $s0, LOOP

For the following C statement, what is the corresponding MIPS assembly code? Assume that the variables f, g, h, i, and j are assigned to registers \(s0, \)s1, \(s2, \)s3, and \(s4, respectively. Assume that the base address of the arrays A and B are in registers \)s6 and $s7, respectively.

B[8]=A[i-j]

Translate the following C code to MIPS. Assume that the variables f, g, h, i , and j are assigned to registers \(s0,\)s1,\(s2,\)s3, and \(s4, respectively. Assume that the base address of the arrays A and B are in registers \)s6 and $s7 respectively. Assume that the elements of the arrays A and B are 4 byte words:

B[8]=A[i]+A[j];

Translate 0×abcdef12into decimal

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