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Question: Based on your answer to 3.38 and 3.39, is (1.666015625×100×1.9760×104)+1.666015625×100×-1.9744×104=1.666015625×100×1.9760×104+-1.9744×104

Short Answer

Expert verified

Based on the answers of 3.38 and 3.39, the given equations are not equal.

Step by step solution

01

Determine the floating-point multiplication

The biased exponents of two numbers will be added as the first step of the floating-point multiplication. Then, the significands will be multiplied to get the product. Check the product for normalization if the necessary product will be normalized by shifting right and incrementing the exponent. Then it will be checked for overflow or underflow. If no underflow or overflow occurs, the product will be rounded off. Finally, the sign of the products will be assigned.

02

Determine whether the equations are equal.

The given equation is

1.666015625×100×1.9760×104+1.666015625×100×-1.9744×104=1.666015625×100×(1.9760×104+-1.9722×104)

Based on the answer of 3.38 and 3.39,

1.666015625×100×1.9760×104+1.666015625×100×-1.9744×104=1.0000000000×2151.666015625×100(1.9760×104+-1.9744×104)=1.1010101010×24

Converting the values into decimal values, we have

1.1010101010×24=26.656251.0000000000×215=32

Since the values are different, it is clear that the two sides of the equation are not equal.

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Most popular questions from this chapter

Question: [10] Write down the binary representation of the decimal number 63.25 assuming the IEEE 754 double precision format.

Question : 3.28 [20] The Hewlett-Packard 2114, 2115, and 2116 used a format with the left most 16 bits being the fraction stored in two’s complement format, followed by another 16-bit field which had the left most 8 bits as an extension of the fraction (making the fraction 24 bits long), and the rightmost 8 bits representing the exponent. However, in an interesting twist, the exponent was stored in sign-magnitude format with the sign bit on the far right! Write down the bit pattern to represent assuming this format. No hidden 1 is used. Comment on how the range and accuracy of this 32-bit pattern compares to the single precision IEEE 754 standards.

Write down the bit pattern in the fraction assuming a floating-point format that uses Binary Coded Decimal (base 10) numbers in the fraction instead of base 2. Assume there are 24 bits, and you do not need to normalize. Is this representation exact?

What is 4365 - 3412 when these values represent signed 12-bit octal numbers stored in sign-magnitude format? The result should be written in octal. Show your work.

Calculate 3.4179687510-3×6.34765625×10-3×1.05625×102 by hand, assuming each of the values are stored in the 16-bit half precision format described in Exercise 3.27 ( and also described in the text). Assume 1 guard, 1 round bit, and 1 sticky bit, and round to the nearest even. Show all the steps, and write your answer in both the 16-bit floating point format and in decimal.

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