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When closing a TCP connection, why is the two-segment-lifetime timeout not necessary on the transition from LAST_ACK to CLOSED?

Short Answer

Expert verified
The 2MSL timeout is not needed because both sides have already closed the connection when transitioning from LAST_ACK to CLOSED.

Step by step solution

01

Understand TCP Connection Termination

TCP connection termination involves a sequence of steps that ensure both ends of the connection have successfully received all transmitted data. There are four key TCP states in this sequence: FIN_WAIT_1, FIN_WAIT_2, LAST_ACK, and CLOSED.
02

The Role of LAST_ACK state

In the LAST_ACK state, the side that sent the first FIN is waiting for an acknowledgment of its FIN from the other side. Once it receives this acknowledgment, it transitions to the CLOSED state.
03

Understanding Two-Segment Lifetime (2MSL)

The Two-Segment Lifetime (2MSL) is a timeout period that ensures all remaining segments in the network are invalid before a connection is completely closed.
04

Examine Transition from LAST_ACK to CLOSED

During the transition from LAST_ACK to CLOSED, the first side has already received acknowledgment of its sent FIN. This means both sides have mutually agreed to close the connection, making the 2MSL timeout unnecessary.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

TCP states
The transmission control protocol (TCP) operates in several distinct states during connection establishment, maintenance, and termination. These states ensure reliable communication and orderly connection teardown. When terminating a connection, some of the most critical states include:

* **FIN_WAIT_1:** When a side requests to end the connection by sending a FIN signal. It waits for the ACK of that FIN.
* **FIN_WAIT_2:** After receiving the ACK for its FIN, it moves to this state to wait for the FIN from the other side.
* **LAST_ACK:** After sending the last FIN acknowledgment, it waits for the final acknowledgment of the FIN it sent.
* **CLOSED:** The state where the connection is fully terminated.

Understanding these states helps in grasping the sequence and reason behind each step in the termination process.
Two-Segment Lifetime
The Two-Segment Lifetime (2MSL) is a critical concept in TCP that ensures all remaining data packets in the network are expired before the connection completely closes.

Why is 2MSL important?
* It allows for the retransmission of lost segments.
* It ensures that outdated segments do not cause confusion for future connections.

This timeout is typically calculated to be twice the maximum segment lifetime, which is an estimated time for a TCP segment to be alive in the network.
LAST_ACK state
In the LAST_ACK state, the side that initiated the connection termination waits for the acknowledgment of its FIN packet. Here’s how it works:

* The sender of the FIN packet waits to receive an ACK from the other side.
* Once the ACK is received, the sender transitions from LAST_ACK to CLOSED state.

This state is crucial as it ensures that both parties are synchronized and agree to close the connection, preventing any loss of data.
CLOSED state
The CLOSED state marks the end of the TCP connection. Once a connection transitions to CLOSED, all resources associated with that connection are released.

Key points about the CLOSED state:
* The connection termination is complete.
* No data transmission occurs.
* Both parties have acknowledged the termination.

It’s important to note that the transition from LAST_ACK to CLOSED does not require the 2MSL timeout. This is because the acknowledgement (ACK) of the FIN segment has already been received, ensuring the connection is properly synchronized and ready to close without risk of confusion from lingering packets.

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Most popular questions from this chapter

Suppose that, when a TCP segment is sent more than once, we take SampleRTT to be the time between the original transmission and the ACK, as in Figure \(5.10(\mathrm{a}) .\) Show that if a connection with a 1-packet window loses every other packet (i.e., each packet is transmitted twice), then EstimatedRTT increases to infinity. Assume TimeOut = EstimatedRTT; both algorithms presented in the text always set TimeOut even larger. Hint: EstimatedRTT \(=\) EstimatedRTT \(+\beta \times(\) SampleRT \(-\) EstimatedRTT).

Suppose, in TCP's adaptive retransmission mechanism, that EstimatedRTT is 90 at some point and subsequent measured RTTs all are 200 . How long does it take before the TimeOut value, as calculated by the Jacobson/Karels algorithm, falls below 300 ? Assume initial Deviation value of 25 ; use \(\delta=1 / 8\).

The Jacobson/Karels algorithm sets TimeOut to be 4 mean deviations above the mean. Assume that individual packet round-trip times follow a statistical normal distribution, for which 4 mean deviations are \(\pi\) standard deviations. Using statistical tables, for example, what is the probability that a packet will take more than TimeOut time to arrive?

Consider a simple UDP-based protocol for requesting files (based somewhat loosely on the Trivial File Transport Protocol, TFTP). The client sends an initial file request, and the server answers (if the file can be sent) with the first data packet. Client and server then continue with a stop-and-wait transmission mechanism. (a) Describe a scenario by which a client might request one file but get another; you may allow the client application to exit abruptly and be restarted with the same port. (b) Propose a change in the protocol that will make this situation much less likely.

Suppose we were to implement remote file system mounting using an unreliable RPC protocol that offers zero-or-more semantics. If a message reply is received, this improves to at-least-once semantics. We define read() to return the specified Nth block, rather than the next block in sequence; this way reading once is the same as reading twice and at-least-once semantics is thus the same as exactly once. (a) For what other file system operations is there no difference between at- leastonce and exactly once semantics? Consider open, create, write, seek, opendir, readdir, mkdir, delete (aka unlink), and rmdir. (b) For the remaining operations, which can have their semantics altered to achieve equivalence of at-least-once and exactly once? What file system operations are irreconcilable with at-least-once semantics? (c) Suppose the semantics of the rmdir system call are now that the given directory is removed if it exists, and nothing is done otherwise. How could you write a program to delete directories that distinguishes between these two cases?

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