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The RPC-based "NFS" remote file system is sometimes considered to have slower than expected write performance. In NFS, a server's RPC reply to a client write request means that the data is physically written to the server's disk, not just placed in a queue. (a) Explain the bottleneck we might expect, even with infinite bandwidth, if the client sends all its write requests through a single logical CHAN channel, and explain why using a pool of channels could help. Hint: You will need to know a little about disk controllers. (b) Suppose the server's reply means only that the data has been placed in the disk queue. Explain how this could lead to data loss that wouldn't occur with a local disk. Note that a system crash immediately after data was enqueued doesn't count because that would cause data loss on a local disk as well. (c) An alternative would be for the server to respond immediately to acknowledge the write request, and to send its own separate CHAN request later to confirm the physical write. Propose different CHAN RPC semantics to achieve the same effect, but with a single logical request/reply.

Short Answer

Expert verified
Write bottleneck occurs due to slow disk I/O; multiple channels distribute workload. Data loss can happen if data is only queued. Two-phase CHAN semantics ensure persistence with preliminary acknowledgment and final confirmation.

Step by step solution

01

Understanding the Bottleneck (Part (a))

In NFS, the server's RPC reply to a client's write request means that the data is physically written to the server's disk. This can cause a bottleneck if the client sends all its write requests through a single CHAN channel because disk I/O operations are slow compared to network bandwidth. Disk controllers can only handle a limited number of I/O operations per second, and a single channel means requests will queue up, waiting for the disk to become available.
02

Using a Pool of Channels (Part (a))

Using a pool of channels can help alleviate the bottleneck. By distributing write requests across multiple channels, the workload is spread out, and multiple disk operations can proceed concurrently. This parallelism can reduce waiting times by taking advantage of the disk controller's ability to handle multiple I/O operations better.
03

Potential Data Loss (Part (b))

If the server's reply indicates only that the data has been placed in the disk queue, rather than being physically written to the disk, it can lead to data loss in cases other than a system crash. For instance, if the disk controller fails or the queue becomes corrupt before the data is written to the disk, the data in the queue is lost without ever being saved, unlike with a local disk where the application often assumes persistence after queueing.
04

Alternative Approach with Confirmation (Part (c))

To address the issue, a two-phase confirmation via CHAN RPC semantics can be used. The server could immediately acknowledge the enqueuing of data with a preliminary reply. Once the data is physically written, the server can send a final confirmation. With this approach, the client first receives an acknowledgment ensuring the request was accepted, followed by a confirmation ensuring data persistence.
05

Implementing CHAN RPC Semantics (Part (c))

The semantics of CHAN RPC could be adjusted such that each write request triggers two replies: an initial acknowledgment reply as soon as the request is enqueued, and a final confirmation reply once the data is physically written. The client can use this information to verify the completeness of the write operation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Remote Procedure Call (RPC)
Remote Procedure Call (RPC) is a protocol that allows a program to request a service from a program located on another computer on a network. When a client sends an RPC write request to the NFS server, the server processes it and responds. This interaction involves network communication, which could introduce delays.
However, NFS write performance issues don't just stem from network delays. The server's reply signifies that data is physically written to the disk, adding to the time taken for each write operation. This sequence is fundamental to understanding write bottlenecks in NFS.
RPC simplifies remote communications by hiding the intricacies of the network, allowing the developer to write the remote service call as if it were a local call. Yet, the underlying processes can still introduce performance challenges that must be managed effectively.
Disk I/O bottleneck
Disk I/O bottlenecks occur when the speed of disk operations lags behind network bandwidth. The server in an NFS system may only handle a finite number of read/write operations per second. Despite having unlimited bandwidth, if the client funnels all write requests through a single logical channel, the disk becomes a bottleneck.
This single channel forces all requests to queue up, causing significant delays. Disk operations are inherently slower compared to network transfers, and this mismatch creates a performance pinch point. Recognizing and mitigating this issue can greatly enhance NFS write performance.
Channel parallelism
Channel parallelism involves spreading out tasks across multiple channels to enhance performance. In the context of NFS, using a pool of channels instead of a single one can alleviate the disk I/O bottleneck.
By distributing write requests across multiple logical channels, the workload is spread over several operations, allowing for concurrent disk activities. This approach leverages the disk controller's ability to handle multiple I/O operations in parallel, reducing wait times and increasing overall system efficiency.
Implementing channel parallelism effectively utilizes hardware capabilities and improves response times for write operations.
Data persistence
Data persistence means that once data is written, it remains available and safe from loss. In NFS, ensuring data persistence is crucial, and relying merely on data being queued can be risky. If a server crashes or the disk controller fails before writing the queued data physically, the enqueued data could be lost.
Local disks often assume persistence once data is queued. However, remote systems like NFS must guarantee that data is physically written to avoid loss. This requires robust methods to confirm that data has transitioned from queued to written state.
Reliable data persistence involves ensuring that the server's acknowledgment corresponds to the actual write operation completion.
Disk controller operations
Disk controllers manage the read/write operations between a computer and its disk drives. They are critical in determining the efficiency of disk I/O processes. In an NFS system, understanding disk controller capabilities is essential for optimizing performance.
Disk controllers can only handle a certain number of operations per second. Knowing this limit helps in designing better systems. For instance, if we know the controller's threshold, we can implement channel parallelism more effectively.
Further, disk controllers often have built-in optimizations like command queueing and out-of-order execution. Leveraging these features can improve data handling and enhance overall system throughput.

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Most popular questions from this chapter

Suppose a TCP connection, with window size 1, loses every other packet. Those that do arrive have RTT \(=1\) second. What happens? What happens to TimeOut? Do this for two cases: (a) After a packet is eventually received, we pick up where we left off, resuming with EstimatedRTT initialized to its pretimeout value and TimeOut double that. (b) After a packet is eventually received, we resume with TimeOut initialized to the last exponentially backed-off value used for the timeout interval. In the following four exercises, the calculations involved are straightforward with a spreadsheet.

Suppose that, when a TCP segment is sent more than once, we take SampleRTT to be the time between the most recent transmission and the ACK, as in Figure \(5.10\) (b). Assume, for definiteness, that TimeOut \(=2 \times\) EstimatedRTT. Sketch a scenario in which no packets are lost but EstimatedRTT converges to a third of the true RTT, and give a diagram illustrating the final steady state. Hint: Begin with a sudden jump in the true RTT to just over the established TimeOut.

Write a test program that uses the socket interface to send messages between a pair of Unix workstations connected by some LAN (e.g., Ethernet, ATM, or FDDI). Use this test program to perform the following experiments. (a) Measure the round-trip latency of TCP and UDP for different message sizes (e.g., 1 byte, 100 bytes, 200 bytes, ..., 1000 bytes). (b) Measure the throughput of TCP and UDP for 1-KB, 2-KB, 3-KB, ...,32-KB messages. Plot the measured throughput as a function of message size. (c) Measure the throughput of TCP by sending \(1 \mathrm{MB}\) of data from one host to another. Do this in a loop that sends a message of some size, for example, 1024 iterations of a loop that sends 1-KB messages. Repeat the experiment with different message sizes and plot the results.

Consider a simple UDP-based protocol for requesting files (based somewhat loosely on the Trivial File Transport Protocol, TFTP). The client sends an initial file request, and the server answers (if the file can be sent) with the first data packet. Client and server then continue with a stop-and-wait transmission mechanism. (a) Describe a scenario by which a client might request one file but get another; you may allow the client application to exit abruptly and be restarted with the same port. (b) Propose a change in the protocol that will make this situation much less likely.

The sequence number field in the TCP header is 32 bits long, which is big enough to cover over 4 billion bytes of data. Even if this many bytes were never transferred over a single connection, why might the sequence number still wrap around from \(2^{32}-1\) to 0 ?

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