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When TCP sends a \(\langle\) SYN, SequenceNum \(=x\rangle\) or \(\langle\) FIN, SequenceNum \(=x\rangle\), the consequent ACK has Acknowledgment \(=x+1\); that is, SYNs and FINs each take up one unit in sequence number space. Is this necessary? If so, give an example of an ambiguity that would arise if the corresponding Acknowledgment were \(x\) instead of \(x+1 ;\) if not, explain why.

Short Answer

Expert verified
Yes, it is necessary to increment the acknowledgment by 1 to avoid confusion between control segments and data segments.

Step by step solution

01

- Understand the basics of sequence and acknowledgment numbers

In TCP, each byte of data has a sequence number. When a segment is sent, it includes the Sequence Number field (indicating the byte number of the first byte in the segment) and the Acknowledgment Number field (indicating the next byte number the sender expects to receive).
02

- Understand SYN and FIN segments

A SYN segment is used to initiate a connection, and a FIN segment is used to terminate a connection. Each of these segments consumes one sequence number space because they need to be uniquely identified and acknowledged.
03

- Analyze the acknowledgment process

When a SYN segment with SequenceNum = x is sent, the receiving end needs to acknowledge it by sending an ACK with Acknowledgment = x + 1. Similarly, when a FIN segment is sent with SequenceNum = x, the receiving end acknowledges it with Acknowledgment = x + 1.
04

- Identify the necessity of incrementing sequence numbers

If the acknowledgment for a SYN or FIN segment were simply x instead of x + 1, it would cause confusion. The sender would not be able to differentiate between an acknowledgment for the control segment (SYN/FIN) and an acknowledgment for data segment x.
05

- Provide an example of ambiguity

Consider a scenario where a SYN is sent with SequenceNum = x, and the receiver sends an acknowledgment without incrementing the sequence number (thus ACK = x). The sender may think the acknowledgment is for some earlier data segment, leading to confusion and potential retransmissions.
06

- Conclusion

To prevent such ambiguities and to clearly distinguish control segments (SYN/FIN) from data segments, it is necessary for the acknowledgment to increment by 1. This practice ensures clarity in communication and proper establishment/termination of connections.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SYN Segments
When initiating a TCP connection, a special packet called a SYN segment is sent. SYN stands for 'synchronize'. This segment is crucial because it helps set the initial sequence number, which is used to keep track of the bytes transmitted in the session.
  • A SYN segment indicates the start of a connection.
  • It includes a sequence number.
  • The receiver acknowledges it by sending back an ACK with an acknowledgment number equal to the sequence number + 1.
Here’s a simple example:
If a SYN segment has SequenceNum = 1000, the acknowledgment from the receiver will be Acknowledgment = 1001.
FIN Segments
A FIN segment (short for 'finish') is used to terminate a TCP connection. It signifies that the sender has finished sending data.
  • A FIN segment indicates the end of a connection.
  • Similar to SYN, it includes a sequence number.
  • The receiver acknowledges this with an acknowledgment number equal to the sequence number + 1.
For instance:
If a FIN segment has SequenceNum = 3000, the acknowledgment will be Acknowledgment = 3001.
Sequence Number Space
The sequence number space in TCP is a range of numbers used to keep track of the position of each byte in a stream of data.
  • Every byte transmitted in a TCP connection has a unique sequence number.
  • SYN and FIN segments also occupy space in the sequence number space.
  • This is essential for ensuring no data is lost or duplicated.
Imagine sequence numbers as labels on individual packets. Each byte's sequence number ensures data arrives in the correct order and can be reassembled properly.
TCP Acknowledgment Process
The acknowledgment process in TCP helps ensure data is received correctly. The receiver sends an acknowledgment number, which represents the next byte it expects to receive.
  • SYN segments trigger acknowledgments (ACK) from the receiver.
  • FIN segments also expect acknowledgments from the receiver.
  • Regular data segments include sequence numbers, and the receiver acknowledges them by sending an ACK for the next byte expected.
For example, if a segment with SequenceNum = 1500 is sent and received correctly, the receiver sends back an ACK with Acknowledgment = 1501. If SYN or FIN segments are involved, the acknowledgment increments by 1 to indicate the control segment has been received.
Ambiguity in TCP Acknowledgment
Ambiguity in TCP acknowledgment can occur if the acknowledgment number for SYN or FIN segments is not incremented.
  • Without incrementing, it’s unclear whether the acknowledgment is for a control segment or for regular data.
  • This can cause confusion and retransmission of data.
Consider an example:
If a SYN segment with SequenceNum = 500 is acknowledged with ACK = 500 (instead of 501), the sender might think the acknowledgment is for some previous data segment. This leads to unnecessary retransmissions and potential connection issues. Hence, to avoid ambiguity, the acknowledgment for SYN and FIN must increment the sequence number by 1. This ensures clarity in communication, making sure the control segments (SYN/FIN) are distinctly acknowledged apart from regular data.

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Most popular questions from this chapter

TCP is a very symmetric protocol, but the client/server model is not. Consider an asymmetric TCP-like protocol in which only the server side is assigned a port number visible to the application layers. Client-side sockets would simply be abstractions that can be connected to server ports. (a) Propose header data and connection semantics to support this. What will you use to replace the client port number? (b) What form does TIME_WAIT now take? How would this be seen through the programming interface? Assume that a client socket could now be reconnected arbitrarily many times to a given server port, resources permitting. (c) Look up the \(\mathrm{rsh} / \mathrm{rlogin}\) protocol. How would the above break this?

One of the purposes of TIME_WAIT is to handle the case of a data packet from a first incarnation of a connection arriving very late and being accepted as data for the second incarnation. (a) Explain why, for this to happen (in the absence of TIME_WAIT), the hosts involved would have to exchange several packets in sequence after the delayed packet was sent but before it was delivered. (b) Propose a network scenario that might account for such a late delivery.

Suppose an idle TCP connection exists between sockets A and B. A third party has eavesdropped and knows the current sequence number at both ends. (a) Suppose the third party sends A a forged packet ostensibly from B and with 100 bytes of new data. What happens? Hint: Look up in Request for Comments 793 what TCP does when it receives an ACK that is not an "acceptable ACK." (b) Suppose the third party sends each end such a forged 100-byte data packet ostensibly from the other end. What happens now? What would happen if \(\mathrm{A}\) later sent 200 bytes of data to B?

Suppose BLAST runs over a 10-Mbps Ethernet, sending \(32 \mathrm{~K}\) messages. (a) If the Ethernet packets can hold 1500 bytes of data, and optionless IP headers are used as well as BLAST headers, how many Ethernet packets are required per message? (b) Calculate the delay due to sending a \(32 \mathrm{~K}\) message over Ethernet (i) directly (ii) broken into pieces as in (a), with one bridge Ignore propagation delays, headers, collisions, and interpacket gaps.

Consider a simple UDP-based protocol for requesting files (based somewhat loosely on the Trivial File Transport Protocol, TFTP). The client sends an initial file request, and the server answers (if the file can be sent) with the first data packet. Client and server then continue with a stop-and-wait transmission mechanism. (a) Describe a scenario by which a client might request one file but get another; you may allow the client application to exit abruptly and be restarted with the same port. (b) Propose a change in the protocol that will make this situation much less likely.

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