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TCP's simultaneous open feature is seldom used. (a) Propose a change to TCP in which this is disallowed. Indicate what changes would be made in the state diagram (and if necessary in the undiagrammed event responses). (b) Could TCP reasonably disallow simultaneous close? (c) Propose a change to TCP in which simultaneous SYNs exchanged by two hosts lead to two separate connections. Indicate what state diagram changes this entails, and also what header changes become necessary. Note that this now means that more than one connection can exist over a given pair of \langlehost, port)s. (You might also look up the first "Discussion" item on page 87 of Request for Comments \(1122 .\) )

Short Answer

Expert verified
Disallow simultaneous open by aborting on SYN receipt in SYN-SENT state. Do not disallow simultaneous close. Allow simultaneous SYNs to create separate connections by adjusting the state diagram and TCP headers for unique identification.

Step by step solution

01

- Disallow Simultaneous Open

To disallow simultaneous open in TCP, modify the TCP state diagram to ensure that when a SYN is received while in the SYN-SENT state, the connection is aborted or reset instead of moving to the SYN-RECEIVED state. This prevents the simultaneous open scenario where both endpoints attempt to open a connection at the same time.
02

- Reasoning for Disallowing Simultaneous Close

Disallowing simultaneous close in TCP wouldn't be practical as it is a natural way for both sides to finish sending and to terminate the connection gracefully. Simultaneous FINs lead to the TIME-WAIT state ensuring any lost segments in the network are managed correctly. Therefore, simultaneous close should be allowed.
03

- Allowing Separate Connections for Simultaneous SYNs

To allow two simultaneous SYNs to lead to two separate connections, change the state diagram to allow a transition such that separate connections can be maintained when SYNs are received simultaneously. This requires each connection between two hosts to be uniquely identified, necessitating changes to the TCP header to include a connection identifier or extended addressing scheme to manage more than one connection between the same pair of host-port sets.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

TCP state diagram
The TCP state diagram is crucial for understanding how connections progress through various states from initiation to termination. It visually represents the transitions between different states such as LISTEN, SYN-SENT, SYN-RECEIVED, ESTABLISHED, FIN-WAIT-1, FIN-WAIT-2, TIME-WAIT, and CLOSED. By modifying this diagram, we can control how TCP handles different scenarios.
For instance, to disallow simultaneous open, when a SYN is received in the SYN-SENT state, the state should transition to an aborted or reset state instead of SYN-RECEIVED. This ensures that both ends do not try to establish the connection concurrently, thereby avoiding conflicting states.
simultaneous open
A simultaneous open occurs when two devices send SYN packets simultaneously, attempting to establish a connection at the same time. This is rare but allowed by standard TCP. However, we can adjust this behavior by changing the TCP state diagram.
Instead of transitioning to SYN-RECEIVED when SYN packets meet in the SYN-SENT state, the connection can be aborted or reset. This change helps to eliminate the ambiguity of state transitions and ensures clear connection paths, avoiding the simultaneous open situation.
Practically, this means updating the state diagram to reflect that any incoming SYN in the SYN-SENT state results in an aborted connection, maintaining a straightforward and unambiguous state flow.
simultaneous close
Simultaneous close happens when both sides of a TCP connection send a FIN packet at nearly the same time. This mechanism helps both parties to agree on closing the connection gracefully.
This process is useful because it leads the connection to progress into the TIME-WAIT state, ensuring any last segments in the network are properly managed before finally closing. Disallowing simultaneous close would undermine the reliability of connection termination in TCP.
Simultaneous close should be maintained in current TCP implementations as it ensures a more robust and error-tolerant closure method.
connection management
Managing TCP connections involves state transitions, the exchange of packets, and proper termination to ensure data integrity and network efficiency. The key processes include three-way handshake for connection establishment and four-way handshake for termination.
The three-way handshake involves SYN, SYN-ACK, and ACK packets, ensuring both ends synchronize and acknowledge the connection. For termination, the four-way handshake uses FIN and ACK packets from both sides to close the connection properly.
Effective connection management ensures reliable data transfer and stable network communications, especially crucial for maintaining multiple connections simultaneously.
TCP header modifications
Modifying TCP's behavior like handling simultaneous SYNs to allow separate connections requires changes to the TCP header. The original TCP header doesn't support multiple connections between the same host-port pairs.
To achieve this, we might introduce a unique connection identifier in TCP headers, helping manage multiple connections by distinguishing each one uniquely even between the same sets of host and port.
This change ensures each concurrent connection is properly isolated and identifiable, reducing ambiguity and enhancing TCP's capability to handle more complex networking scenarios.

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Most popular questions from this chapter

Suppose a client \(C\) repeatedly connects via TCP to a given port on a server \(S\), and that each time it is \(\mathrm{C}\) that initiates the close. (a) How many TCP connections a second can C make here before it ties up all its available ports in TIME_WAIT state? Assume client ephemeral ports are in the range 1024-5119, and that TIME_WAIT lasts 60 seconds. (b) Berkeley-derived TCP implementations typically allow a socket in TIME WAIT state to be reopened before TIME_WAIT expires, if the highest sequence number used by the old incarnation of the connection is less than the ISN used by the new incarnation. This solves the problem of old data accepted as new; however, TIME_WAIT also serves the purpose of handling late final FINs. What would such an implementation have to do to address this and still achieve strict compliance with the TCP requirement that a FIN sent anytime before or during a connection's TIME_WAIT receive the same response?

The sequence number field in the TCP header is 32 bits long, which is big enough to cover over 4 billion bytes of data. Even if this many bytes were never transferred over a single connection, why might the sequence number still wrap around from \(2^{32}-1\) to 0 ?

Suppose an RPC request is of the form "Increment the value of field X of disk block \(\mathrm{N}\) by \(10 \%\)." Specify a mechanism to be used by the executing server to guarantee that an arriving request is executed exactly once, even if the server crashes while in the middle of the operation. Assume that individual disk block writes are either complete or else the block is unchanged. You may also assume that some designated "undo log" blocks are available. Your mechanism should include how the RPC server is to behave at restart.

When TCP sends a \(\langle\) SYN, SequenceNum \(=x\rangle\) or \(\langle\) FIN, SequenceNum \(=x\rangle\), the consequent ACK has Acknowledgment \(=x+1\); that is, SYNs and FINs each take up one unit in sequence number space. Is this necessary? If so, give an example of an ambiguity that would arise if the corresponding Acknowledgment were \(x\) instead of \(x+1 ;\) if not, explain why.

The RPC-based "NFS" remote file system is sometimes considered to have slower than expected write performance. In NFS, a server's RPC reply to a client write request means that the data is physically written to the server's disk, not just placed in a queue. (a) Explain the bottleneck we might expect, even with infinite bandwidth, if the client sends all its write requests through a single logical CHAN channel, and explain why using a pool of channels could help. Hint: You will need to know a little about disk controllers. (b) Suppose the server's reply means only that the data has been placed in the disk queue. Explain how this could lead to data loss that wouldn't occur with a local disk. Note that a system crash immediately after data was enqueued doesn't count because that would cause data loss on a local disk as well. (c) An alternative would be for the server to respond immediately to acknowledge the write request, and to send its own separate CHAN request later to confirm the physical write. Propose different CHAN RPC semantics to achieve the same effect, but with a single logical request/reply.

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