Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The Nagle algorithm, built into most TCP implementations, requires the sender to hold a partial segment's worth of data (even if PUSHed) until either a full segment accumulates or the most recent outstanding ACK arrives. (a) Suppose the letters abcdefghi are sent, one per second, over a TCP connection with an RTT of \(4.1\) seconds. Draw a timeline indicating when each packet is sent and what it contains. (b) If the above were typed over a full-duplex Telnet connection, what would the user see? (c) Suppose that mouse position changes are being sent over the connection. Assuming that multiple position changes are sent each RTT, how would a user perceive the mouse motion with and without the Nagle algorithm?

Short Answer

Expert verified
Packets are sent at 0s, 4.1s, 8.2s, 12.3s, and 16.4s with Nagle algorithm. Over Telnet, characters show up in chunks every 4.1s. Mouse movements would be choppier with Nagle, smoother without it.

Step by step solution

01

Understanding the Nagle Algorithm

The Nagle algorithm requires the sender to collect data to form a full segment or wait for an acknowledgment (ACK) for the previously sent data before sending new data. This helps reduce the amount of small packets on the network, thus improving efficiency.
02

Determine Packet Sending Time

Given letters abcdefghi are sent one per second with an RTT of 4.1 seconds, check when packets are sent. The first packet can be sent immediately, then Nagle algorithm holds the next packets until either full segment or ACK is received.
03

Timeline for Sent Packets

Since the RTT is 4.1 seconds, a full packet is sent every 4.1 seconds. 1. At time 0 seconds, 'a' is sent. 2. At time 4.1 seconds, 'b' and 'c' are sent. 3. At time 8.2 seconds, 'd', 'e', 'f' are sent. 4. At time 12.3 seconds, 'g', 'h' are sent. 5. At time 16.4 seconds, 'i' is sent.
04

Observing Over Telnet Connection

With the above timeline, if typed over Telnet connection: - After 4.1 seconds, 'abc' appears. - After 8.2 seconds, 'def' appears. - After 12.3 seconds, 'gh' appears. - After 16.4 seconds, 'i' appears.
05

Mouse Movement Observation

With Nagle algorithm, mouse motion may appear choppy as updates are sent in bursts every RTT. Without Nagle, every small position change is sent immediately, resulting in smoother motion.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

TCP segment handling
In the context of the Transmission Control Protocol (TCP), segment handling is crucial for efficient communication. TCP breaks down large data into smaller, manageable segments to optimize transmission. Each segment is then sent independently over the network.

When a sender transmits data, the TCP layer constructs these segments, ensuring they fit into the Maximum Segment Size (MSS) defined for the connection. The receiver reassembles these segments into the original data.

Efficient TCP segment handling is vital for network performance as it balances the payload size with control data, maintaining data integrity and sequencing.
RTT (Round-Trip Time)
Round-Trip Time (RTT) is the duration it takes for a signal to travel from the sender to the receiver and back. This metric is crucial in TCP as it influences data flow control and acknowledgement strategies.

An accurate RTT measurement helps the TCP layer adjust retransmission timers, reducing latency and improving throughput. For example, if the RTT is 4.1 seconds, the sender must wait this interval for an acknowledgment before sending more data.

Understanding RTT helps in optimizing real-time applications, ensuring timely delivery and improving user experience.
Real-time communication efficiency
Efficiency in real-time communication depends on minimizing delays and optimizing data flow. Techniques like the Nagle algorithm aim to reduce the number of small packets, thereby decreasing network congestion and improving overall performance.

In real-time applications, such as online gaming or video conferencing, every millisecond counts. Properly implemented TCP features ensure data is transmitted with minimal delay, resulting in a seamless user experience.
  • Grouping small data packets into larger segments
  • Acknowledging reception promptly
  • Optimizing retransmission strategies
Telnet connection behavior
Telnet is a protocol allowing remote access to another computer. Telnet connections involve interactive input and output, making them sensitive to transmission delays.

With the Nagle algorithm enabled, Telnet may sometimes buffer input data, sending it only when a segment is full or an acknowledgment is received. This can cause noticeable delays in displaying characters typed by the user over a network with a high RTT.

Users may experience delayed or bursty text output, affecting usability. Hence, the Nagle algorithm may be disabled for interactive services like Telnet to ensure instant feedback.
Mouse movement perception
Mouse movement perception in networked applications is crucial for a smooth user experience. When using a TCP connection, the Nagle algorithm can affect how fluidly mouse movements are perceived.

With the Nagle algorithm enabled, mouse position updates may be collected into larger segments and sent less frequently, leading to jerky or choppy motion due to the RTT delays. Conversely, without the Nagle algorithm, each position change is sent immediately, resulting in smoother and more responsive movement.

For applications relying on real-time updates, such as remote desktop software, disabling the Nagle algorithm can significantly enhance user satisfaction.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A sender on a TCP connection that receives a 0 advertised window periodically probes the receiver to discover when the window becomes nonzero. Why would the receiver need an extra timer if it were responsible for reporting that its advertised window had become nonzero (i.e., if the sender did not probe)?

You are hired to design a reliable byte-stream protocol that uses a sliding window (like TCP). This protocol will run over a 100-Mbps network. The RTT of the network is \(100 \mathrm{~ms}\), and the maximum segment lifetime is 60 seconds. (a) How many bits would you include in the AdvertisedWindow and SequenceNum fields of your protocol header? (b) How would you determine the numbers given above, and which values might be less certain?

Write a test program that uses the socket interface to send messages between a pair of Unix workstations connected by some LAN (e.g., Ethernet, ATM, or FDDI). Use this test program to perform the following experiments. (a) Measure the round-trip latency of TCP and UDP for different message sizes (e.g., 1 byte, 100 bytes, 200 bytes, ..., 1000 bytes). (b) Measure the throughput of TCP and UDP for 1-KB, 2-KB, 3-KB, ...,32-KB messages. Plot the measured throughput as a function of message size. (c) Measure the throughput of TCP by sending \(1 \mathrm{MB}\) of data from one host to another. Do this in a loop that sends a message of some size, for example, 1024 iterations of a loop that sends 1-KB messages. Repeat the experiment with different message sizes and plot the results.

TCP is a very symmetric protocol, but the client/server model is not. Consider an asymmetric TCP-like protocol in which only the server side is assigned a port number visible to the application layers. Client-side sockets would simply be abstractions that can be connected to server ports. (a) Propose header data and connection semantics to support this. What will you use to replace the client port number? (b) What form does TIME_WAIT now take? How would this be seen through the programming interface? Assume that a client socket could now be reconnected arbitrarily many times to a given server port, resources permitting. (c) Look up the \(\mathrm{rsh} / \mathrm{rlogin}\) protocol. How would the above break this?

Request for Comments 1122 states (of TCP): A host MAY implement a "half-duplex" TCP close sequence, so that an application that has called CLOSE cannot continue to read data from the connection. If such a host issues a CLOSE call while received data is still pending in TCP, or if new data is received after CLOSE is called, its TCP SHOULD send an RST to show that data was lost. Sketch a scenario involving the above in which data sent by (not to!) the closing host is lost. You may assume that the remote host, upon receiving an RST, discards all received data still unread in buffers.

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free