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If host \(\mathrm{A}\) receives two SYN packets from the same port from remote host \(\mathrm{B}\), the second may be either a retransmission of the original or else, if B has crashed and rebooted, an entirely new connection request. (a) Describe the difference as seen by host A between these two cases. (b) Give an algorithmic description of what the TCP layer needs to do upon receiving a SYN packet. Consider the duplicate/new cases above, and the possibility that nothing is listening to the destination port.

Short Answer

Expert verified
Retransmission has the same sequence number; a new connection has a different sequence number. Algorithm: check if the port is listening, compare sequence numbers, send appropriate responses based on the match.

Step by step solution

01

- Understanding the TCP Three-Way Handshake

The TCP three-way handshake is essential for establishing a connection between a client and a server. The process involves:1. SYN: Client sends a synchronization packet to initiate the connection.2. SYN-ACK: Server acknowledges the SYN packet and sends its own SYN packet.3. ACK: Client acknowledges the server’s SYN-ACK packet.Understanding this process helps in differentiating between retransmission and a new connection request.
02

- Identifying Retransmission vs New Connection Request

When host A receives a second SYN packet from the same port on host B, it needs to determine whether this is a retransmission or a new connection request. The key differences are:- Retransmission: Likely due to the original SYN-ACK being lost or delayed. The sequence number in the SYN packet will be identical to the original.- New Connection Request: Host B has crashed and rebooted, and the sequence number in the SYN packet will differ from the original.
03

- Algorithm for Handling a SYN Packet

The TCP layer on host A can follow this algorithm:1. Check if the destination port is listening: - If not, send an RST (reset) packet in response to the SYN packet.2. If the port is listening, check the sequence number in the SYN packet: - If the sequence number matches the existing connection’s initial sequence number, treat it as a retransmission. Send SYN-ACK again. - If the sequence number differs, treat it as a new connection request and initiate the TCP three-way handshake.3. Maintain a state table that logs the sequence numbers of connection attempts to help differentiate between retransmissions and new requests.
04

- Managing States

Host A must manage connection state information to differentiate between retransmissions and new connections:- For each connection, store the initial sequence number and other relevant information in a state table.- When a SYN packet is received, compare the sequence number with the recorded initial sequence number to determine if it is a retransmission or a new connection request.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SYN packet
The SYN packet is the cornerstone of the TCP three-way handshake. When initiating a connection, the client sends a SYN (synchronize) packet to the server. This packet does two essential things: it synchronizes sequence numbers, and it sets up the initial parameters for the TCP session. The SYN packet contains a sequence number, which helps in identifying and reassembling data packets in the correct order. In the context of a retransmission, the sequence number in the SYN packet will be identical to the original. However, if the remote host has crashed and rebooted, a new sequence number will be generated.
This difference in the sequence number is crucial for Host A to discern whether the second SYN packet it received is for resending due to a lost packet or for initiating a new connection.
Sequence number
Sequence numbers in TCP are vital for maintaining data integrity and ordering. Each packet sent over a TCP connection contains a sequence number, which indicates the first byte of the data contained in that packet. This allows the receiving end to reassemble the packets in the correct order.
  • **Retransmission:** If Host A receives a SYN packet with the same sequence number as an already established connection, it’s likely a retransmission, possibly due to the original SYN-ACK being lost or delayed.
  • **New Connection:** If Host B has crashed and rebooted, the new SYN packet will have a different sequence number.
Recognizing the difference ensures the TCP layer can effectively manage connection states, preventing confusion between old and new connection requests. A simple comparison of the incoming sequence number with existing ones helps determine the next course of action.
Connection state
Managing connection states is a critical function of the TCP layer. Upon receiving a SYN packet, Host A must correctly identify the state of the connection. Here’s an algorithm that can be followed:
1. **Check Listening Status:** If the port isn’t listening, Host A should send a Reset (RST) packet back, indicating that the connection can’t be established.
2. **Verify Sequence Number:** When the port is listening, compare the sequence number in the SYN packet:
  • If it matches the existing connection’s initial sequence number, it’s a retransmission, prompting a SYN-ACK.
  • If it differs, treat it as a new connection request, initiating the TCP three-way handshake.
3. **State Table Maintenance:** To manage multiple connections efficiently, Host A should maintain a state table that logs initial sequence numbers and other critical data.
This state management allows Host A to accurately differentiate between a new connection request and a retransmission, ensuring reliable and orderly communication.

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Most popular questions from this chapter

Suppose TCP operates over a 1-Gbps link. (a) Assuming TCP could utilize the full bandwidth continuously, how long would it take the sequence numbers to wrap around completely? (b) Suppose an added 32-bit timestamp field increments 1000 times during the wraparound time you found above. How long would it take for the timestamp to wrap around?

TCP is a very symmetric protocol, but the client/server model is not. Consider an asymmetric TCP-like protocol in which only the server side is assigned a port number visible to the application layers. Client-side sockets would simply be abstractions that can be connected to server ports. (a) Propose header data and connection semantics to support this. What will you use to replace the client port number? (b) What form does TIME_WAIT now take? How would this be seen through the programming interface? Assume that a client socket could now be reconnected arbitrarily many times to a given server port, resources permitting. (c) Look up the \(\mathrm{rsh} / \mathrm{rlogin}\) protocol. How would the above break this?

Consider a simple UDP-based protocol for requesting files (based somewhat loosely on the Trivial File Transport Protocol, TFTP). The client sends an initial file request, and the server answers (if the file can be sent) with the first data packet. Client and server then continue with a stop-and-wait transmission mechanism. (a) Describe a scenario by which a client might request one file but get another; you may allow the client application to exit abruptly and be restarted with the same port. (b) Propose a change in the protocol that will make this situation much less likely.

Propose an extension to TCP by which one end of a connection can hand off its end to a third host; that is, if \(\mathrm{A}\) were connected to \(\mathrm{B}\), and \(\mathrm{A}\) handed off its connection to \(\mathrm{C}\), then afterwards \(\mathrm{C}\) would be connected to \(\mathrm{B}\) and \(\mathrm{A}\) would not. Specify the new states and transitions needed in the TCP state transition diagram, and any new packet types involved. You may assume all parties will understand this new option. What state should A go into immediately after the handoff?

Request for Comments 1122 states (of TCP): A host MAY implement a "half-duplex" TCP close sequence, so that an application that has called CLOSE cannot continue to read data from the connection. If such a host issues a CLOSE call while received data is still pending in TCP, or if new data is received after CLOSE is called, its TCP SHOULD send an RST to show that data was lost. Sketch a scenario involving the above in which data sent by (not to!) the closing host is lost. You may assume that the remote host, upon receiving an RST, discards all received data still unread in buffers.

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