Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Suppose a workstation has an I/O bus speed of \(800 \mathrm{Mbps}\) and memory bandwidth of 2 Gbps. Assuming DMA in and out of main memory, how many interfaces to 45-Mbps T3 links could a switch based on this workstation handle?

Short Answer

Expert verified
The switch can handle 17 T3 links.

Step by step solution

01

Understand the Requirements

The problem is asking how many 45-Mbps T3 links can be managed by a system with an I/O bus speed of 800 Mbps and a memory bandwidth of 2 Gbps. The data is transferred using Direct Memory Access (DMA).
02

Determine the Total Data Transfer Rate Required

Each T3 link requires 45 Mbps. If there are multiple T3 links, the total required bandwidth will be the sum of the individual link bandwidths. Let the number of T3 links be represented as 'n'. The total bandwidth required is then: \[ \text{Total Bandwidth Required} = 45n \text{ Mbps} \]
03

Identify the Bottleneck

Compare the required bandwidth to the available system resources. The I/O bus speed is 800 Mbps, and the memory bandwidth is 2 Gbps. The lower of these values will be the bottleneck. In this case, the I/O bus speed of 800 Mbps is the bottleneck.
04

Calculate the Maximum Number of T3 Links

Using the bottleneck bandwidth (I/O bus speed), determine the maximum number of T3 links that can be handled: \[ 45n \text{ Mbps} \ \text{Maximize for } n \] Setting the total bandwidth equal to the I/O bus speed, solve for 'n': \[ 45n \text{ Mbps} = 800 \text{ Mbps} \ n = \frac{800}{45} \approx 17.78 \] Since partial T3 links are not feasible, take the integer part: \[ n = 17 \]

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

I/O Bus Speed
The I/O bus speed refers to the rate at which data can be transferred between the computer's CPU and its peripheral devices. Measured in megabits per second (Mbps) or gigabits per second (Gbps), this speed determines how quickly data can move to and from input/output devices.
The I/O bus speed is crucial because it represents a system's capability to handle external data. In our exercise, the workstation has an I/O bus speed of 800 Mbps.
When considering multiple data streams, the I/O bus speed acts as a limiting factor, or bottleneck. For instance, transferring data from multiple T3 links simultaneously will depend on whether the combined data rate of these links exceeds or meets the I/O bus speed.
Memory Bandwidth
Memory bandwidth is the measure of the data transfer rate between the memory (RAM) and other parts of the computer. It is a key factor affecting a computer's overall performance, especially during high-speed data processing.
The bandwidth is typically measured in Gbps. In the given problem, the workstation has a memory bandwidth of 2 Gbps. This means the memory can handle a data transfer rate of up to 2 gigabits per second.
However, even if the memory bandwidth is high, the actual speed at which data is transferred to and from peripheral devices depends on the I/O bus speed. So, while memory bandwidth is important, the practical data throughput will always be capped by the lower of the I/O bus or memory bandwidth.
T3 Links
T3 links are a type of digital data transmission used in telecommunications. Each T3 link offers a data transmission rate of 45 Mbps. They are commonly used for high-speed internet connections and data transfer between large networks.
When working with multiple T3 links, their combined data rate must be evaluated against the system's capabilities. For example, if each T3 link transmits at 45 Mbps, managing multiple T3 links will require summing up these rates.
In the workstation problem, the goal is to determine how many T3 links the system can handle with an I/O bus speed of 800 Mbps. The bottleneck here is the I/O bus speed, so we calculate the maximum number by dividing the total allowed data rate (800 Mbps) by the rate per T3 link (45 Mbps). The result is around 17.78, meaning the system can handle up to 17 T3 links, as partial links are not feasible.
This calculation ensures that data transfer does not exceed the system's I/O bus capacity, ensuring efficient and uninterrupted data flow between the T3 links and the system.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the source routing example of Section 3.1.3, the address received by B is not reversible and doesn't help B know how to reach A. Propose a modification to the delivery mechanism that does allow for reversibility. Your mechanism should not require giving all switches globally unique names.

Suppose a 10-Mbps Ethernet hub (repeater) is replaced by a 10-Mbps switch, in an environment where all traffic is between a single server and \(N\) "clients." Because all traffic must still traverse the server-switch link, nominally there is no improvement in bandwidth. (a) Would you expect any improvement in bandwidth? If so, why? (b) What would your answer be if the original hub were token ring rather than Ethernet? (c) What other advantages and drawbacks might a switch offer versus a hub?

An Ethernet switch is simply a bridge that has the ability to forward some number of packets in parallel, assuming the input and output ports are all distinct. Suppose two such \(N\)-port switches, for a large value of \(N\), are each able to forward individually up to three packets in parallel. They are then connected to one another in series by joining a pair of ports, one from each switch; the joining link is the bottleneck as it can, of course, carry only one packet at a time. (a) Suppose we choose two connections through this combined switch at random. What is the probability that both connections can be forwarded in parallel? Hint: This is the probability that at most one of the connections crosses the link. (b) What if three connections are chosen at random?

A stage of an \(n \times n\) banyan network consists of \((n / 2) 2 \times 2\) switching elements. The first stage directs packets to the correct half of the network, the next stage to the correct quarter, and so on, until the packet is routed to the correct output. Derive an expression for the number of \(2 \times 2\) switching elements needed to make an \(n \times n\) banyan network. Verify your answer for \(n=8\).

The CS-PDU for AAL 5 contains up to 47 bytes of padding, while the AAL3/4 CSPDU only contains up to 3 bytes of padding. Explain why the effective bandwidth of AAL 5 is always the same as, or higher than, that of AAL.3/4, given a PDU of a particular size.

See all solutions

Recommended explanations on Computer Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free