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Why is it important for protocols configured on top of the Ethernet to have a length field in their header, indicating how long the message is?

Short Answer

Expert verified
The length field ensures message integrity, proper buffer allocation, efficient processing, and helps in error detection by indicating the exact size of the message.

Step by step solution

01

Understanding the Role of the Length Field

The length field in a protocol header indicates the size of the message payload. It helps in determining where the message ends, especially in variable-length messages.
02

Message Integrity and Separation

By specifying the exact length of the message, the length field ensures that no extra data is mistakenly considered part of the message. This helps maintain the integrity of the received data.
03

Buffer Allocation

Protocols rely on the length field to allocate the correct amount of memory for incoming messages. This ensures efficient use of resources and prevents buffer overflow errors.
04

Efficient Processing

The length field allows for quicker and more efficient processing of messages by network devices, as they know exactly how much data to expect and process without reading unnecessary bytes.
05

Error Detection

Having the length field helps in error detection. If the length of the received data does not match the indicated length, it signals a possible error in transmission, prompting necessary corrective actions.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

message integrity
Message integrity is crucial when transmitting data over a network. The length field in the Ethernet protocol plays a vital role in maintaining it. When the length field specifies the exact size of the message, it ensures that no additional or extraneous data is considered part of the message.

Imagine sending a letter in an envelope. If the envelope’s size matches the letter, the recipient knows exactly where the letter ends and can be sure they received it completely. Similarly, the length field does the same for digital messages.

By having a clear definition of the message size, the receiver can detect if any data has been added, tampered with, or truncated. Think of it as a safeguard to ensure the message arrives just as it was sent, preserving the integrity of the data.
buffer allocation
Buffer allocation is another important aspect of networking. When data is received, it is temporarily stored in a buffer before processing. The length field in the Ethernet header informs the receiving device about the exact size of the incoming message.

This information allows the receiver to allocate the right amount of memory in the buffer. Efficient buffer allocation is not just about having enough space; it’s also about avoiding excess. Using the exact memory required for each message prevents wasting resources and helps in managing multiple messages efficiently.

Picture a warehouse where packages are stored. If the warehouse knows the size of each incoming package, it can arrange storage space precisely. This avoids clutter and ensures that the packages fit perfectly without taking more space than necessary. Similarly, the length field helps in making sure the data is well-managed in memory buffers.
error detection
Error detection is essential for reliable data transmission. The length field aids in this by acting as a basic check. When a message is received, the actual length of the message should match the value indicated in the length field.

If the lengths don’t match, it signals a problem. For example, the message might have been corrupted, or some data may have been lost during transmission. This discrepancy can prompt the system to take corrective actions, such as requesting the sender to retransmit the message.

Consider sending a file via email. If the recipient finds the file size is different from what was expected, it’s an indication something went wrong. The length field in the Ethernet protocol serves a similar function, ensuring that any mismatch triggers an investigation to keep the data integrity intact.

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Most popular questions from this chapter

Draw a timeline diagram for the sliding window algorithm with SWS = RWS = 4 frames for the following two situations. Assume the receiver sends a duplicate acknowledgement if it does not receive the expected frame. For example, it sends DUPACK[2] when it expects to see FRAME[2] but receives FRAME[3] instead. Also, the receiver sends a cumulative acknowledgment after it receives all the outstanding frames. For example, it sends ACK[5] when it receives the lost frame FRAME[2] after it already received FRAME[3], FRAME[4], and FRAME[5]. Use a timeout interval of about \(2 \times\) RTT. (a) Frame 2 is lost. Retransmission takes place upon timeout (as usual). (b) Frame 2 is lost. Retransmission takes place either upon receipt of the first DUPACK or upon timeout. Does this scheme reduce the transaction time? Note that some end-to-end protocols (e.g., variants of TCP) use a similar scheme for fast retransmission.

Suppose a \(100-\mathrm{Mbps}\) delayed-release token ring has 10 stations, a ring latency of \(30 \mu \mathrm{s}\), and an agreed-upon TTRT of \(350 \mu \mathrm{s}\). (a) How many synchronous frame bytes could each station send, assuming all are allocated the same amount? (b) Assume stations \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) are in increasing order on the ring. Due to uniform synchronous traffic, the TRT without asynchronous data is \(300 \mu \mathrm{s}\). B sends a \(200-\mu \mathrm{s}(2.5-\mathrm{Kb})\) asynchronous frame. What TRT will \(\mathrm{A}, \mathrm{B}\), and \(\mathrm{C}\) then see on their next measurement? Who may transmit such a frame next?

Ethernets use Manchester encoding. Assuming that hosts sharing the Ethernet are not perfectly synchronized, why does this allow collisions to be detected soon after they occur, without waiting for the CRC at the end of the packet?

Suppose that one byte in a buffer covered by the Internet checksum algorithm needs to be decremented (e.g., a header hop count field). Give an algorithm to compute the revised checksum without rescanning the entire buffer. Your algorithm should consider whether the byte in question is low order or high order.

Suppose five stations are waiting for another packet to finish on an Ethernet. All transmit at once when the packet is finished and collide. (a) Simulate this situation up until the point when one of the five waiting stations succeeds. Use coin flips or some other genuine random source to determine backoff times. Make the following simplifications: Ignore interframe spacing, ignore variability in collision times (so that retransmission is always after an exact integral multiple of the \(51.2-\mu\) s slot time), and assume that each collision uses up exactly one slot time. (b) Discuss the effect of the listed simplifications in your simulation versus the behavior you might encounter on a real Ethernet.

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