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Describe a protocol combining the sliding window algorithm with selective ACKs. Your protocol should retransmit promptly, but not if a frame simply arrives one or two positions out of order. Your protocol should also make explicit what happens if several consecutive frames are lost.

Short Answer

Expert verified
Combine a sliding window algorithm with selective ACKs to retransmit missing frames promptly and efficiently handle lost frames.

Step by step solution

01

Introduction to Sliding Window Algorithm

The sliding window algorithm is a technique for efficiently managing data frames between a sender and receiver. It ensures flow control and manages the number of frames sent without overwhelming the receiver.
02

Understanding Selective Acknowledgments (Selective ACKs)

Selective ACKs allows the receiver to acknowledge received frames individually, rather than cumulatively. This means the receiver can inform the sender about all received frames, even if some are out of order.
03

Combining Sliding Window with Selective ACKs

Combine the sliding window mechanism with selective ACKs to effectively manage out-of-order frames. The sender maintains a window of frames allowed to be sent but only retransmits the missing frames as indicated by ACKs.
04

Implementation to Handle One or Two Frames Out of Order

If a frame arrives one or two positions out of order, the receiver sends a selective ACK for the frames that arrived correctly. The sender only needs to retransmit the missing frames, ensuring efficient use of bandwidth.
05

Protocol for Consecutive Frames Lost

If several consecutive frames are lost, the receiver sends selective ACKs for the last correctly received frame. After a timeout period, the sender detects the missing frames and retransmits only the unacknowledged frames accordingly.
06

Detecting and Handling Retransmissions

Implement a timeout mechanism where the sender waits for a specific period for ACKs. If no ACK is received for certain frames, the sender retransmits those specific frames instead of the entire window, optimizing efficiency.
07

Summary of the Protocol

The sliding window with selective ACKs protocol promptly retransmits only the needed frames. It avoids retransmissions if only one or two frames are out of order and effectively handles multiple lost frames using selective ACKs and timeout-based retransmission.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sliding window algorithm
The sliding window algorithm is a core concept in networking that efficiently manages the flow of data frames between a sender and a receiver. It's essentially a buffer of frames that the sender can transmit without waiting for an acknowledgment from the receiver for each frame. This approach ensures that data transmission is continuous, reducing idle time and increasing bandwidth utilization. By using a sliding window, the sender can send multiple frames before needing confirmation, and the receiver can process these frames without being overwhelmed. The window 'slides' forward as acknowledgments are received, allowing new frames to be sent. This technique is crucial for maintaining a balance between transmission speed and reception capability.
selective acknowledgments
Selective acknowledgments (SACKs) are an enhancement over standard cumulative acknowledgments. With SACKs, the receiver can inform the sender about all the received frames, even if they are out of order. This is incredibly useful in efficient error management. For example, if a receiver gets frames 1, 2, and 4, but not 3, it can acknowledge frames 1, 2, and 4 specifically to the sender. The sender, upon receiving these ACKs, will only need to retransmit frame 3 rather than retransmitting frames 1 to 4. This selective acknowledgment setup allows more precise communication about received data, enhances efficiency, minimizes unnecessary retransmissions, and optimizes the network's usage of bandwidth.
flow control
Flow control is a mechanism that ensures the sender does not overwhelm the receiver with more data than it can handle. This concept is elegantly managed by the sliding window algorithm. The window size is a crucial parameter that dynamically adjusts based on the available buffer space and the current network conditions. When the receiver's buffer is full, it signals the sender to stop sending additional frames until some of the buffered frames are processed. By using flow control, the protocol maintains a smooth data transfer process, reduces packet loss, and prevents network congestion. Effective flow control is essential for achieving optimal performance in a sliding window protocol.
retransmission strategy
The retransmission strategy defines how the sender deals with lost or corrupted frames. In the sliding window protocol with selective acknowledgments, the sender only retransmits those frames specifically identified as missing by the receiver, as opposed to retransmitting every frame from the point of the last acknowledgment. This method is significantly more efficient as it minimizes the number of frames resent and conserves bandwidth. When the receiver detects a missing frame based on its sequence, it sends a selective ACK that tells the sender exactly which frame needs to be resent. This targeted retransmission improves overall network performance and reduces unnecessary data transfer, leading to faster recovery from errors.
timeout mechanism
The timeout mechanism is crucial for detecting when a frame needs retransmission. If the sender does not receive an acknowledgment for certain frames within a specified time period, it interprets this lack of response as a sign of data loss. The sender will then retransmits the specific unacknowledged frames. This timeout duration must be carefully configured: too short, and it may lead to unnecessary retransmissions; too long, and it may result in significant delays. The timeout mechanism ensures reliability in data transfer by providing a fallback for the acknowledgment process. It complements selective ACKs by covering scenarios where ACKs are lost or network conditions prevent timely acknowledgments.

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Most popular questions from this chapter

Suppose we want to transmit the message 1011001001001011 and protect it from errors using the CRC-8 polynomial \(x^{8}+x^{2}+x^{1}+1\). (a) Use polynomial long division to determine the message that should be transmitted. (b) Suppose the leftmost bit of the message is inverted due to noise on the transmission link. What is the result of the receiver's CRC calculation? How does the receiver know that an error has occurred?

Suppose five stations are waiting for another packet to finish on an Ethernet. All transmit at once when the packet is finished and collide. (a) Simulate this situation up until the point when one of the five waiting stations succeeds. Use coin flips or some other genuine random source to determine backoff times. Make the following simplifications: Ignore interframe spacing, ignore variability in collision times (so that retransmission is always after an exact integral multiple of the \(51.2-\mu\) s slot time), and assume that each collision uses up exactly one slot time. (b) Discuss the effect of the listed simplifications in your simulation versus the behavior you might encounter on a real Ethernet.

Coaxial cable Ethernet was limited to a maximum of \(500 \mathrm{~m}\) between repeaters, which regenerate the signal to \(100 \%\) of its original amplitude. Along one \(500-\mathrm{m}\) segment, the signal could decay to no less than \(14 \%\) of its original value \((8.5 \mathrm{~dB})\). Along \(1500 \mathrm{~m}\), then, the decay might be \((0.14)^{3}=0.3 \%\). Such a signal, even along \(2500 \mathrm{~m}\), is still strong enough to be read; why then are repeaters required every \(500 \mathrm{~m}\) ? $$ \begin{array}{l|l} \hline \text { Item } & \text { Delay } \\ \hline \text { Coaxial cable } & \text { propagation speed } .77 c \\ \text { Link/drop cable } & \text { propagation speed .65c } \\ \text { Repeaters } & \text { approximately 0.6 } \mu \text { s each } \\ \text { Transceivers } & \text { approximately 0.2 } \mu \text { s each } \\ \hline \end{array} $$

Suppose you want to send some data using the BISYNC framing protocol, and the last 2 bytes of your data are DLE and ETX. What sequence of bytes would be transmitted immediately prior to the CRC?

Suppose that \(N\) Ethernet stations, all trying to send at the same time, require \(N / 2\) slot times to sort out who transmits next. Assuming the average packet size is 5 slot times, express the available bandwidth as a function of \(N\).

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