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Suppose we want to transmit the message 11001001 and protect it from errors using the CRC polynomial \(x^{3}+1\) (a) Use polynomial long division to determine the message that should be transmitted. (b) Suppose the leftmost bit of the message is inverted due to noise on the transmission link. What is the result of the receiver's CRC calculation? How does the receiver know that an error has occurred?

Short Answer

Expert verified
Transmit 11001001100. An inverted bit results in a non-zero remainder, indicating an error.

Step by step solution

01

Convert Binary Message to Polynomial

Convert the message 11001001 into its corresponding polynomial. Each binary digit represents a coefficient of the polynomial.The message 11001001 corresponds to the polynomial:\[ x^7 + x^6 + x^3 + 1 \]
02

Determine the CRC Divisor Polynomial

The CRC polynomial given is \( x^3 + 1 \).
03

Append Zeroes to the Original Message

Append three zeroes (since the highest degree of the divisor polynomial is 3) to the original message to prepare for division. The new message is 11001001000.
04

Perform Polynomial Long Division

Divide the polynomial corresponding to 11001001000 by \( x^3 + 1 \) using polynomial long division. This determines the remainder.1. Divide highest degree terms: \( x^7 / x^3 = x^4 \)2. Subtract \((x^4 \times (x^3 + 1))\) from the polynomial.3. Repeat the process with the next highest degree result.After completing the division, we find the remainder.
05

Find the Remainder

The remainder after the polynomial long division is 100. This remainder is the CRC checksum.
06

Form the Transmitted Message

Combine the original message with the remainder. The data to be transmitted is 11001001100.
07

Simulate an Error

Invert the leftmost bit of the transmitted message due to noise. The corrupted message is now 01001001100.
08

Receiver's CRC Calculation

The receiver performs the same polynomial division (01001001100 divided by \( x^3 + 1 \)). If the message is error-free, the remainder should be zero.After division, the receiver finds a non-zero remainder, indicating an error.
09

Error Detection

The receiver knows an error has occurred because the remainder is non-zero after performing polynomial division on the received corrupted message.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cyclic Redundancy Check
Cyclic Redundancy Check (CRC) is a popular method for detecting errors in digital data. It’s widely used in networking and storage devices. The primary idea is to treat the digital message as a polynomial. To detect errors, we append a CRC checksum to the original message. This checksum is derived using a predefined CRC polynomial.
By dividing the message polynomial by the CRC polynomial, we obtain a remainder. This remainder becomes the CRC checksum. When the message is transmitted, the receiver performs the same division. If the remainder matches the transmitted CRC checksum, then no errors are detected. If there is a mismatch, it indicates some data corruption during transmission.
Polynomial Long Division
Polynomial Long Division is a mathematical technique used to perform the division of polynomials. In the context of CRC, we use polynomial long division to divide the appended message by the CRC polynomial to find the checksum.
To divide a polynomial, we follow these steps:
  • Identify the highest degree terms of both the message and the CRC polynomials.
  • Divide the leading term of the message by the leading term of the CRC polynomial and multiply the result by the entire CRC polynomial.
  • Subtract this product from the original message, resulting in a new polynomial.
  • Repeat this process with the new polynomial until the degree of the remainder is less than the degree of the CRC polynomial.

The final remainder after this division is the CRC checksum.
Error Detection in Networks
Error Detection in Networks is crucial to ensure data integrity during transmission. CRC is a commonly used error detection method due to its effectiveness in identifying burst errors and its lightweight computational requirements.
When a message is transmitted, it can get corrupted due to noise or other interference. To detect errors, the sender appends a CRC checksum to the message. Upon receiving the message, the receiver performs the same polynomial division. If the calculated CRC remainder does not match the received checksum, the receiver concludes that an error has occurred.
This mechanism significantly improves the reliability of data transmission in various network protocols and storage systems.
Data Transmission Integrity
Data Transmission Integrity ensures that data sent from a sender arrives at the receiver without errors. CRC plays a vital role in maintaining this integrity. By appending a CRC checksum to the data, we can detect and sometimes even correct data errors.
The process involves several steps:
  • The sender generates a CRC checksum from the original data.
  • This checksum is appended to the data before transmission.
  • During transmission, any noise or interference can introduce errors into the data.
  • The receiver recalculates the CRC checksum from the received data.
  • If the checksum matches the one sent with the data, the transmission is validated. If not, the receiver knows an error occurred.

This error detection method is efficient and helps ensure robust communication, especially in digital networks and storage systems.

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Most popular questions from this chapter

Draw a timeline diagram for the sliding window algorithm with SWS = RWS = 4 frames for the following two situations. Assume the receiver sends a duplicate acknowledgement if it does not receive the expected frame. For example, it sends DUPACK[2] when it expects to see FRAME[2] but receives FRAME[3] instead. Also, the receiver sends a cumulative acknowledgment after it receives all the outstanding frames. For example, it sends ACK[5] when it receives the lost frame FRAME[2] after it already received FRAME[3], FRAME[4], and FRAME[5]. Use a timeout interval of about \(2 \times\) RTT. (a) Frame 2 is lost. Retransmission takes place upon timeout (as usual). (b) Frame 2 is lost. Retransmission takes place either upon receipt of the first DUPACK or upon timeout. Does this scheme reduce the transaction time? Note that some end-to-end protocols (e.g., variants of TCP) use a similar scheme for fast retransmission.

Suppose that one byte in a buffer covered by the Internet checksum algorithm needs to be decremented (e.g., a header hop count field). Give an algorithm to compute the revised checksum without rescanning the entire buffer. Your algorithm should consider whether the byte in question is low order or high order.

Suppose we want to transmit the message 1011001001001011 and protect it from errors using the CRC-8 polynomial \(x^{8}+x^{2}+x^{1}+1\). (a) Use polynomial long division to determine the message that should be transmitted. (b) Suppose the leftmost bit of the message is inverted due to noise on the transmission link. What is the result of the receiver's CRC calculation? How does the receiver know that an error has occurred?

Suppose that we attempt to run the sliding window algorithm with SWS = RWS = 3 and with MaxSeqNum \(=5 .\) The Nth packet DATA[ \(N]\) thus actually contains \(N\) mod 5 in its sequence number field. Give an example in which the algorithm becomes confused; that is, a scenario in which the receiver expects DATA[5] and accepts DATA[0]-which has the same transmitted sequence number-in its stead. No packets may arrive out of order. Note this implies MaxSeqNum \(\geq 6\) is necessary as well as sufficient.

Suppose a \(100-\mathrm{Mbps}\) delayed-release token ring has 10 stations, a ring latency of \(30 \mu \mathrm{s}\), and an agreed-upon TTRT of \(350 \mu \mathrm{s}\). (a) How many synchronous frame bytes could each station send, assuming all are allocated the same amount? (b) Assume stations \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) are in increasing order on the ring. Due to uniform synchronous traffic, the TRT without asynchronous data is \(300 \mu \mathrm{s}\). B sends a \(200-\mu \mathrm{s}(2.5-\mathrm{Kb})\) asynchronous frame. What TRT will \(\mathrm{A}, \mathrm{B}\), and \(\mathrm{C}\) then see on their next measurement? Who may transmit such a frame next?

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